Use if / else inside a for-loop and change values of array depending on condition
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Hi all,
I am stuck with the following step and I can't find the solution. The code I need is to change the columns of an array depending on the column index. For odd numbers, without change, for even numbers change the sign.
The size of the array should be variable by dimensions 1 and 2.
Here is what I tryied. Can someone help me please.
Thanks
Size_1 = 5;
Size_2 = 6;
array = ones(Size_1,Size_2);
for i=1:Size_2
if rem(i,2)==0
new_array_2 = array(:,i);
else
new_array_2 = -1*array(:,i);
end
end
new_array should be this
new_array =
1 -1 1 -1 1 -1
1 -1 1 -1 1 -1
1 -1 1 -1 1 -1
1 -1 1 -1 1 -1
1 -1 1 -1 1 -1
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채택된 답변
madhan ravi
2019년 2월 9일
No loops needed:
size1=5;
size2=6;
A=ones(size1,size2);
A(:,2:2:end)=-A(:,2:2:end)
댓글 수: 2
madhan ravi
2019년 2월 9일
See the answer below.
Reasons:
- You forgot to preallocate new_array_2.
- You forgot to index new_array_2.
추가 답변 (1개)
madhan ravi
2019년 2월 9일
If you insist loop then:
Size_1 = 5;
Size_2 = 6;
A = ones(Size_1,Size_2);
for i=1:Size_2
if rem(i,2)==0
A(:,i)=-A(:,i); % if even change the sign
else
A(:,i)=A(:,i);
end
end
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