solving variable in exponential equation

i am trying to use the equation: y = ae^rt; to solve for t; y = final population, a = initial population, r = rate increasing. i'm using editor but it is not working. i know the answer to my equation is around 210, however my code below is not working:
sysm y a r t
y == a * ((exp((r*t));
a = 300;
r = .10;
y = 600;
solve t

댓글 수: 6

SP
SP 2019년 2월 4일
getting this error when running it after putting it in editor
Error: File: untitled Line: 2 Column: 22
Invalid expression. When calling a function or indexing a variable, use parentheses. Otherwise, check for mismatched delimiters.
madhan ravi
madhan ravi 2019년 2월 4일
편집: madhan ravi 2019년 2월 4일
syms y a r t
eqn=y == a * exp((r*t));
t=solve(eqn,t);
a = 600;
r = .10;
y = 600;
Final_t=subs(t)
Yields:
t =
log(y/a)/r %-> log(600/600)/r==>0 , so why do you say 210?
SP
SP 2019년 2월 4일
when you actually solve the math using the eqaution on paper, the correct answer is 208:
so your code must be wrong since t is suppose to equal about 208
madhan ravi
madhan ravi 2019년 2월 4일
what's r ? it's not there in the picture.
The paper uses values around 300 that are no-where to be found in the 600-ish values you posted.
SP
SP 2019년 2월 4일
i apoligize a = 300, that was my mistake

댓글을 달려면 로그인하십시오.

답변 (2개)

KSSV
KSSV 2019년 2월 4일

0 개 추천

syms y a r t
eqn = y == a * ((exp((r*t))));
S = solve(eqn,t) ;
a = 600;
r = .10;
y = 600;
S = subs(S,a) ;
S = subs(S,r) ;
S = subs(S,y) ;
Stephan
Stephan 2019년 2월 4일
편집: Stephan 2019년 2월 4일

0 개 추천

syms t
a = 600;
r = .10;
y = 600;
eq = y - a * (exp(r*t)) == 0;
tsol = solve(eq,t)

댓글 수: 4

SP
SP 2019년 2월 4일
error:
Undefined function or variable 'y'.
SP
SP 2019년 2월 4일
this worked, however when i enter, i get this:
tsol =
log(y/a)/r
how can i can the actual number value, the anser in terms of variables is right, but i am looking for a number
Stephan
Stephan 2019년 2월 4일
error is corrected. the solution is zero. this is obviously.
use
clear a y r t

댓글을 달려면 로그인하십시오.

질문:

SP
2019년 2월 4일

댓글:

2019년 2월 4일

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by