Deleting Entries in an Array

I am working with a 1627x11 array, labelled A, and I want to delete the entries that have 0 in the 9th column (i.e delete the whole row).

V = A(:,9);

vals=find(V==0);

A(vals)=[ ];

after running that code, the array converts to an 1x16617 double - which is not wat I anticipated nor want.

To reiterate, the 9th column which has a sort of counter is used to keep track of which point I am working with, and I do not want to include the rows which are in the 0th point.

Rows 0 to 1280 contains 0 in the 9th column (this was done by observing the array), so I should have a 347x11 array after running the code.

What am I doing wrong

Answer 1

[Brian Hart]

Hi Ramitha,

You almost got it. For your last line of code, try

A(vals,:)=[];

The way you tried it at first uses linear lindexing (see sub2ind)

[Hans123]

Thanks Brian, ti worked perfectly!

[Stephen23]

Simpler and more efficient to use logical indexing (without find):

A(A(:,9)==0,:) = [];

[Hans123]

that's great! Thanks Stephen

Answer 2

[madhan ravi]

A(~any(A(:,9),2),:)=[]