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Need help with a while loop to take numbers off.

조회 수: 2 (최근 30일)
Nicolo Zaza
Nicolo Zaza 2012년 7월 21일
마감: MATLAB Answer Bot 2021년 8월 20일
Alright so I have counting algorithm but i need it to extract elements from an original source and after extracting them and storing I need matlab to discard them so they dont get count again. How do i do this? My code: if true
DATA = [ 60 0 40 -20 40 -40 50 -30 30 -60 0 -30 40 -30 60];
L = length(DATA);
E = [1:L];
N = 1;
while N < L
N = N + 1;
if N < 3
continue
end
X(N) = [abs(DATA(N)-DATA(N-1))];
Y(N) = [abs(DATA(N-1)-DATA(N-2))];
if X < Y
continue
else
RANGE(N) = Y(N);
XMEAN(N) = [.5*(DATA(N-1)+DATA(N-2))]
DATA (N -2) = []
DATA (N-1) = []
N = N - 2
end
for I = N:L
L = L - 2
E(I) = E(I+1);
end
end
end
  댓글 수: 1
Nicolo Zaza
Nicolo Zaza 2012년 7월 21일
Sorry to not finish expressing my question. So what I'm using right now is if true
DATA(N-2) = []
&
DATA(N-1) = []
end
to delete the values used to calculate RANGE because once range is calculated I dont need to calculate it again for those same points. Is there a better matlab function/code to accomplish this need?

답변 (1개)

Image Analyst
Image Analyst 2012년 7월 21일
편집: Image Analyst 2012년 7월 21일
Yes, that will delete elements but you're indexing elements and that will change, not to mention the length of your DATA array keeps getting shorter as you delete elements to eventually as N approaches L you'll get an index out of range error.
What are you really trying to do? Can't you just extract arrays and subtract them, and use diff? Or use hist if you want to count values?
data_n = DATA(3:end)
data_nm1 = DATA(2:end-1)
data_nm2 = DATA(1:end-2)
X = abs(data_n - data_nm1)
Y = abs(data_n - data_nm2)
RANGE = y
xMean = 0.5 * (data_nm1 - data_nm2)
% I have no idea what E is supposed to represent.
  댓글 수: 3
Nicolo Zaza
Nicolo Zaza 2012년 7월 21일
Yes I've seen it but is written in C and is hard to manipulate for me. I dont have much programming knowledge. Besides the program I need is pretty simple compared to that

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