Read text file efficiently
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Hi all,
Does anybody has an idea how to efficiently read a *.txt-file in following format:
1/ 2/2019 01:30 -1.59 0.39 253
1/ 2/2019 01:45 -1.78 0.35 250
1/ 2/2019 02:00 -1.94 0.31 246
1/ 2/2019 02:15 -2.07 0.26 240
I would like to have 8 columns (day, month, year,hour, minute, param1, param2, param3).
The file also has some headers btw.
Like to hear your advise!
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Image Analyst
2019년 1월 25일
Don't forget to attach your text file again, if you still need help.
There are lots of input options, like importdata(), textscan(), etc. if readtable() doesn't work.
답변 (2개)
Walter Roberson
2019년 1월 25일
fid = fopen('YourFile.txt', 'rt');
data = cell2mat( textscan(fid, '%f/%f/%f %f:%f %f %f %f', 'collectoutput', true);
fclose(fid);
댓글 수: 3
Walter Roberson
2019년 1월 26일
filename = 'test.txt';
fid = fopen(filename, 'rt');
location_cell = textscan(fid, 'Location: %f° %f'' %f" %c %f° %f'' %f" %c%*[^\n]', 1, 'Headerlines', 1);
data = cell2mat( textscan(fid, '%f/%f/%f %f:%f %f %f %f', 'collectoutput', true, 'Headerlines', 6) );
fclose(fid);
lat = location_cell{1} + location_cell{2}/60 + location_cell{3}/3600;
if strcmpi(location_cell{4}, 's'); lat = -lat; end
long = location_cell{5} + location_cell{6}/60 + location_cell{7}/3600;
if strcmpi(location_cell{8}, 'w'); long = -long; end
%outputs: lat, long, data
Mjan88
2019년 1월 27일
Walter Roberson
2019년 1월 27일
You could try reducing HeaderLines to 4 on the second textscan. But I tested on your supplied file and the output looked fine to me.
카테고리
도움말 센터 및 File Exchange에서 Text Data Preparation에 대해 자세히 알아보기
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