Hi,
I have an array like:
0.2 2 3
1 3 4
1 4 6
0.8 4 6
2 5 1
1 6 2
0.4 6 2
Now I want to code that MATLAB sums up the values of the 1st column in the rows where the value of the 2nd and 3rd column match.
So the result should look like this below:
0.2 2 3
1 3 4
1.8 4 6
2 5 1
1.4 6 2
I hope someone can help me, thank you!

댓글 수: 3

Bob Thompson
Bob Thompson 2019년 1월 23일
"where the value of the 2nd and 3rd column match."
How do the values of the 2nd and 3rd column match in any of these rows?
In general form this should be fairly easy with logic indexing.
yinki23
yinki23 2019년 1월 23일
Sorry if I was unspecific.
For example, rows no.3 and no.4 both have 4 and 6 in columns no.2 and no.3. So I want to sum these 2 rows up in column 1 (1+0.8). Same with rows no.6 and no.7.
I hope this helps you understand my question.
James Tursa
James Tursa 2019년 1월 23일
Are the values in columns 2 and 3 always positive integers?

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 채택된 답변

Andrei Bobrov
Andrei Bobrov 2019년 1월 23일

0 개 추천

A = [0.2 2 3
1 3 4
1 4 6
0.8 4 6
2 5 1
1 6 2
0.4 6 2];
[a,~,c] = unique(A(:,2:3),'rows','stable');
out = [accumarray(c,A(:,1)),a];

댓글 수: 1

yinki23
yinki23 2019년 1월 23일
Thank you so much! Works perfect for me!

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추가 답변 (1개)

s
s 2019년 1월 23일

0 개 추천

clc;
clear all;
A = [0.2 2 3;1 3 4;1 4 6;0.8 4 6;2 5 1;1 6 2;0.4 6 2];
B = size (A,1);
Result = [];
n = 0;
for i = 1:1:B-1
if (A(i,2) == A(i+1,2) && A(i,3) == A(i+1,3))
n = n+1;
end
end
for j = 1:1:B-n
if (A(j,2) == A(j+1,2) && A(j,3) == A(j+1,3))
Sum = A(j,1)+A(j+1,1);
Result = [Result; Sum A(j,2) A(j,3)]
A([j+1],:) = [];
else
Result = [Result; A(j,1) A(j,2) A(j,3)]
end
end
This should help

카테고리

도움말 센터File Exchange에서 Logical에 대해 자세히 알아보기

질문:

2019년 1월 23일

답변:

s
s
2019년 1월 23일

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