fplot(@(x) x*(sin(x))^2*cos(x),[-2*pi 2*pi]);
[xMin1 fvalmin1] = fminbnd('-x*(sin(x))^2*cos(x)', -6, 6)
returns xMin1 = 1.0954
fvalmin1 = -0.3963
How is this possible, look at the plot?

댓글 수: 3

madhan ravi
madhan ravi 2019년 1월 20일
Why do you say it's a bug?
Stephen Wilkerson
Stephen Wilkerson 2019년 1월 20일
Not where the minimum is! look at the plot
Stephen Wilkerson
Stephen Wilkerson 2019년 1월 20일
Solved, The function doesn't really do much, it give you the nearest point that's a minimum to it's starting point. In my case it woud be 0 as the starting point. Typical

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Walter Roberson
Walter Roberson 2019년 1월 20일

0 개 추천

No bug. fminbnd is a local minimizer, not a global minimizer.

댓글 수: 3

Zhe Yu
Zhe Yu 2022년 7월 17일
편집: Torsten 2022년 7월 17일
Hi Roberson,
I have a similar problem with fminbnd, see code below
a=-200; b=-979.8997; c=7.1833e+05; d=24.4232;e=-6.6083;
x1=0; x2=4.1135e-06;
f=@(x)a-(a-b)*cos(c*(x-x1)) + d*e*sin(c*(x-x1))
f = function_handle with value:
@(x)a-(a-b)*cos(c*(x-x1))+d*e*sin(c*(x-x1))
fplot(f, [x1 x2])
[xmin, min]=fminbnd(f, x1, x2)
xmin = 1.5712e-06
min = -679.5775
We could see from the plot the minimum value should be around -996 and there should be only one local minimum. But fminbnd returns -679.
Thanks a lot in advance!
Best Regards,
Zhe
Torsten
Torsten 2022년 7월 17일
편집: Torsten 2022년 7월 17일
Since the changes in the x-values are in the order of 1e-6, you must choose a smaller value for TolX:
a=-200; b=-979.8997; c=7.1833e+05; d=24.4232;e=-6.6083;
x1=0; x2=4.1135e-06;
f=@(x)a-(a-b)*cos(c*(x-x1)) + d*e*sin(c*(x-x1))
f = function_handle with value:
@(x)a-(a-b)*cos(c*(x-x1))+d*e*sin(c*(x-x1))
fplot(f, [x1 x2])
options = optimset('TolX',1e-8);
[xmin, min]=fminbnd(f, x1, x2, options)
xmin = 2.8422e-07
min = -996.4246
Zhe Yu
Zhe Yu 2022년 7월 17일
Hi Torsten, thank you very much!

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질문:

2019년 1월 20일

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2022년 7월 17일

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