Matlab stuck at Warning about Integers

Hi people,
I need help. I'm running a code and I am getting stuck at line 51 that reads:
sortedData = sort(cutData(tstart:tend));
baseline = median(sortedData(1:((0.2)*length(cutData(tstart:tend)))));
deltaF(i) = (cutData(i) - baseline)/baseline;
This is the message I keep getting:
> In scrapAnalysis (line 51)
Warning: Integer operands are required for colon operator when used as index

댓글 수: 1

Walter Roberson
Walter Roberson 2019년 1월 16일
length(cutData(tstart:tend) is going to be the same as tend-tstart+1 . But suppose that does not happen to be an exact multiple of 5, so 0.2 times the value does not turn out to be an integer?

답변 (3개)

Fangjun Jiang
Fangjun Jiang 2019년 1월 16일

0 개 추천

With this, do you get it?
>> a=rand(1,100);
>> b=a(2:10);
>> c=a(2:0.9:10);
Warning: Integer operands are required for colon operator when used as index.
Star Strider
Star Strider 2019년 1월 16일

0 개 추천

Without knowing more about ‘cutData’, it’s difficult to provide a specific solution. Subscripts must be integers greater than 0, or logicals
Assuming that ‘t’ is your time vector associated with ‘cutData’, try this:
tstart = ...;
tend = ...;
idx1 = find(t >= tstart, 1, 'first');
idx2 = find(t <= tend, 1, 'last');
sortedData = sort(cutData(idx1:idx2));
Something like that should do what you want. You will have to experiment with it with your code.
Mark Dawnson
Mark Dawnson 2019년 1월 17일

0 개 추천

Thanks for all the answers. I'll try these and let you know !

댓글 수: 1

Star Strider
Star Strider 2019년 1월 17일
It would also help to know the complete error message. (Please copy all the red text in your Command Window and paste it to a Comment here).
There are at least two lines that could be throwing that error. We have no idea which one it is.

이 질문은 마감되었습니다.

질문:

2019년 1월 16일

마감:

2021년 8월 20일

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