How do you generate a registered output from Stateflow?
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If I have an output from a Stateflow diagram; in the generated HDL code the output is assigned from the next state decision logic (combinatorial) _next signal and not from the clocked process, _reg signal. As best practice is to have all outputs from a module being registered a unit delay is added to the output external to the stateflow. However when the generated code is synthesised this register is identified as an equivalent register to the equivalent _reg signal and removed, generating a warning.
How do I generate an output from stateflow that is sourced from the _reg signal as opposed to the the _next signal so that I do not need to put unit delays external to the stateflow diagram?
답변 (2개)
Michael Felger
2023년 5월 26일
0 개 추천
Update: starting with R2022b, the ClockDrivenOutput parameter for stateflow is available for Moore charts.
With this, registered output is generated.
카테고리
도움말 센터 및 File Exchange에서 Stateflow에 대해 자세히 알아보기
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