How can I solve the error: error using csvread Too many output arguments?

I am trying to do some calculations with the data extracted from some csv files. It return the error: Error using csvread. Too many output arguments.
Error in myDataProcessV2 (line 13)
[VgAll,IdAll]=csvread(Data_File(j).name,'B251:B602','E251:E602');
What is the correct way to do it?
SrcDIR=uigetdir('Choose the source folder!');
cd(SrcDIR);
Data_File=dir('*.csv');
counts=size(Data_File);
onOffRatioCollection=zeros(counts(1),1);
SSCollection=zeros(counts(1),1);
mobilityCollection=zeros(counts(1),1);
VonCollection=zeros(counts(1),1);
hysCollection=zeros(counts(1),0);
for j=1:counts(1)
[VgAll,IdAll]=csvread(Data_File(j).name,'B251:B602','E251:E602');
IdSize=size(IdAll);
IdSize(1)=IdSize(1)/2;
Id=IdAll(1:IdSize(1));
Vg=VgAll(1:IdSize(1));
if j == 1
lgIdCollection=zeros(IdSize(1),counts(1));
end
lgId=zeros(IdSize);
sqrtId=zeros(IdSize);
for i=1:IdSize(1)
lgId(i)=log10(Id(i));
sqrtId(i)=sqrt(Id(i));
end
lgIdCollection(1:IdSize,j)=lgId;
onOffRatioCollection(j)=seekOnOffRatio(Id);
SSCollection(j)=seekSS(lgId,Vg);
[VonLocation,VonCollection(j)]=seekVon(Id,Vg,lgId);
[kmax,Vth]=seekVth(Id,Vg,VonLocation,sqrtId);
hysCollection(j)=seekHys(IdAll,VgAll,VonLocation,176);
mobilityCollection(j)=seekMobility(kmax);
end

답변 (1개)

Star Strider
Star Strider 2019년 1월 13일

0 개 추천

The csvread function has only one output.
Perhaps you were thinking of the xlsread (link) function?

댓글 수: 4

It gives the same error when I use xlsread.
You can only provide one range at a time for csvread or xlsread .
In particular you cannot read into two different variables by providing two different ranges. You will need to either make two different calls or else make a single call for reading in B251:E602 and throwing away the entries you do not need.
Alternately you could use detectImportOptions() and modify the results to select the variables you want to read, and then use readtable() passing in the filename and the modified options.
Thank you very much!

댓글을 달려면 로그인하십시오.

카테고리

질문:

2019년 1월 13일

댓글:

2019년 1월 15일

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by