필터 지우기
필터 지우기

App Designer: How to delete items from listbox?

조회 수: 60 (최근 30일)
Marie Eckert
Marie Eckert 2019년 1월 12일
댓글: Luna 2021년 2월 4일
Hello everybody,
I want to make it possible to delete the selected item of a listbox by pushing a button. I'm using App Designer.
With the following code I'm getting the error message "Matrix index is out of range for deletion.". But if the first item is selected, nothing happens at all.
% Button pushed function: deleteButton
function deleteButtonPushed(app, event)
hListBox = app.ListBox;
currentItems = get(hListBox);
[~, index] = ismember(hListBox.Value, hListBox.Items);
newItems = currentItems;
newItems(index) = [];
set(hListBox,newItems);
end
So, I guess that's not the way to delete. So I tried to replace the selected item by another one. Just to test if it's possible to change anything in the listbox
newItems(index) = newItems(end);
set(hListBox,newItems);
Like this, I get the following message:
"Error using matlab.ui.control.ListBox/set You cannot set the read-only property 'BeingDeleted' of ListBox."
Can somebody help me? After trying and googling for hours, I'm not even sure if it's possible to change anything in the listbox at runtime.
(Matlab R2018b)
Thank you!!

채택된 답변

Luna
Luna 2019년 1월 12일
편집: Luna 2019년 1월 12일
Hi Marie,
Below code will delete your corresponding item.
function ButtonPushed(app, event)
[~,idx] = ismember(app.ListBox.Value,app.ListBox.Items);
app.ListBox.Items(idx) = [];
end
The below part in your code currentItems will give you the properties of the list box not the Item List in the listbox.
That's how get method works. Get method, gets the properties of the object you are referring in a struct. So that's why you see an error, you can see but you can't set all of the properties of an object because some of them might be protected.
hListBox = app.ListBox;
currentItems = get(hListBox);
When you debug your code(put red dot inside the pushbutton callback and evaluate the line currentItems = get(hListBox) with one step forward), you will see currentItems will give you the below properties:
currentItems =
struct with fields:
Multiselect: 'off'
Value: 'Item 1'
Items: {'Item 1' 'Item 3' 'Item 4'}
ItemsData: []
ValueChangedFcn: [function_handle]
Parent: [1×1 Figure]
HandleVisibility: 'on'
BusyAction: 'queue'
BeingDeleted: 'off'
Interruptible: 'on'
CreateFcn: ''
DeleteFcn: ''
Type: 'uilistbox'
Tag: ''
UserData: []
Enable: 'on'
Visible: 'on'
FontName: 'Helvetica'
FontSize: 12
FontWeight: 'normal'
FontAngle: 'normal'
FontColor: [0 0 0]
BackgroundColor: [1 1 1]
InnerPosition: [147 333 100 74]
Position: [147 333 100 74]
OuterPosition: [147 333 100 74]
  댓글 수: 8
Ricky Zhang
Ricky Zhang 2021년 2월 1일
편집: Ricky Zhang 2021년 2월 1일
careful: seems it doesn't work when ItemsData is not empty. app.ListBox.Value will return the corresponding item's data instead.
Luna
Luna 2021년 2월 4일
Assuming your cell array A is below:
A = {'Item1',[],2,3,'','Item2'};
Then you have to use cellfun to detect each element isempty or not.
empty_idx = cellfun(@isempty, A)
Basically empty_idx will be as follows:
% empty_idx =
% 1×6 logical array
% 0 1 0 0 1 0
% >>
First you should have check all the Items and their data types inside your item list array (most probably a cell or can be categorical array you can check it in the documentation ) you defined for the ListBox.

댓글을 달려면 로그인하십시오.

추가 답변 (1개)

Khaldoun Swid
Khaldoun Swid 2020년 12월 8일
app.ListBox.Items=cellstr(num2str([]));

카테고리

Help CenterFile Exchange에서 Interactive Control and Callbacks에 대해 자세히 알아보기

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by