필터 지우기
필터 지우기

matlab coder error Directly accessing field or property of nonscalar struct or object not supported for code generation.

조회 수: 32 (최근 30일)
This works in Matlab but not in Coder, Why?
s1=string({OPS_FLT(:).ACFT_ID})
s2=OPS_FLT(2).ACFT_ID
uuindex=find(strcmpi(s1,s2))
My array is defineded as:
OPS_FLT(1).ACFT_ID="apple"
OPS_FLT(2).ACFT_ID="orange"
I need to find orange from the array but the code has to be compatible in coder. It says: Directly accessing field or property of nonscalar struct or object not supported for code generation in ({OPS_FLT(:).ACFT_ID})
  댓글 수: 1
cui,xingxing
cui,xingxing 2023년 4월 6일
It is hoped that future versions will support this feature, for example, the current R2023a supports "end+1" C/C++ code generation, which would greatly reduce the concerns of developers.

댓글을 달려면 로그인하십시오.

답변 (1개)

Andy
Andy 2019년 1월 14일
편집: Andy 2019년 1월 16일
Hi Upol. Presently, referencing a component from an array of non-scalar values (accessing a field in a struct array) is not allowed in code generation.
As a workaround, for the time being you can rewrite the code to avoid the non-scalar access:
function uuindex = foo
OPS_FLT = struct('ACFT_ID', {"apple", "orange"});
uuindex=[];
for k = numel(OPS_FLT)
if OPS_FLT(k).ACFT_ID == OPS_FLT(2).ACFT_ID
uuindex = [uuindex, k];
end
end
end
*EDIT: I've modified code from version I original posted since it used another feature that also would not compile.
  댓글 수: 3
Andy
Andy 2019년 5월 22일
Hi Xie,
When running this through codegen "lines" ends up typed as a 1x:? struct array. As such you getting the error message about directly accessing a field of a nonscalar struct.
Could you try converting the line "A = lines.theta" into a for loop that copies each individual theta out to A? In other words change: A=lines.theta into:
A=zeros(1, size(lines,2));
for i=1:size(lines,2)
A(i)=lines(i).theta;
end
Also, I think you may have a problem with the following:
lines = struct('point1',[0,0],'point2',[0,0],'theta',0,'rho',0);
lines = repmat(line,1,0);
You pass "line" to repmat rather than "lines", "line" is a matlab function that returns an object.
This will end up causing a runtime error when you run the generated mex. You can resolve it either by commenting out this code or changing what you pass to repmat from "line" to "lines" (which is what I think you meant to do).
TripleSSSS
TripleSSSS 2020년 6월 10일
I'd suggest using
A=coder.nullcopy(zeros(1, size(lines,2)));
instead of
A=zeros(1, size(lines,2));

댓글을 달려면 로그인하십시오.

카테고리

Help CenterFile Exchange에서 MATLAB Coder에 대해 자세히 알아보기

제품


릴리스

R2018b

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by