problem with function handle

alpha

alpha =

  function_handle with value:

    @(z)(z-b)/a

>> qa

qa =

  function_handle with value:

    @(z)sqrt((1./alpha.^2)-p.^2)

>> t = integral(qa,0,3)
Undefined operator '.^' for input arguments of type 'function_handle'.

Error in @(z)sqrt((1./alpha.^2)-p.^2)

Error in integralCalc/iterateScalarValued (line 314)
                fx = FUN(t);

Error in integralCalc/vadapt (line 132)
            [q,errbnd] = iterateScalarValued(u,tinterval,pathlen);

Error in integralCalc (line 75)
        [q,errbnd] = vadapt(@AtoBInvTransform,interval);

Error in integral (line 88)
Q = integralCalc(fun,a,b,opstruct);

Answer 1

[madhan ravi]

EDITED

syms z
a=1; % an example datas
b=2;
p=3;
alpha=(z-b)/a;
qa=sqrt((1./(alpha.^2)-p.^2));
t = integral(matlabFunction(qa),0,3)

[Saneesh Ali]

thank you sir

[madhan ravi]

Anytime :)

[Stephen23]

@madhan ravi: you define function alpha, but where do you use it?

[Torsten]

Alternatively:

qa=@(z)sqrt(1./alpha(z).^2-p.^2);

[madhan ravi]

@Torsten,

Thank you