Crossover applications in matlab

조회 수: 2 (최근 30일)
Johan Johan
Johan Johan 2019년 1월 6일
댓글: Walter Roberson 2019년 1월 7일
I want to apply crossover betweem x1 and x2
x1=[ -1.0000 - 1.0000i 2.0000 - 2.0000i 3.0000 - 3.0000i];
x2=[ -4.0000 - 4.0000i 5.0000 - 5.0000i 6.0000 - 6.0000i];
CrossoverIndex=1;
>> c2 = [x2(1:CrossoverIndex) x1(CrossoverIndex+1:end)];
But i found this error:
Error using horzcat
Dimensions of matrices being concatenated are not consistent.
Can any one help me how can i solve the error.

채택된 답변

Walter Roberson
Walter Roberson 2019년 1월 7일
you show x1 and x2 as row vectors but your code is p1 and p2. If p1 and p2 are column vectors you would have problems with your [] operation if the crossover was not exactly half way . II suspect you should use ; between the parts.
  댓글 수: 4
Johan Johan
Johan Johan 2019년 1월 7일
Thank you very much, the problem is solved if using the transpose operation :
c2 = [x2(1:CrossoverIndex)' x1(CrossoverIndex+1:end)'];
Walter Roberson,do you know why solved by add the transpose operation ?
Walter Roberson
Walter Roberson 2019년 1월 7일
If the code you posted were the only code that were in place, then it would have been correct. I suspect that you are passing those values into a function that is transposing them.

댓글을 달려면 로그인하십시오.

추가 답변 (0개)

카테고리

Help CenterFile Exchange에서 Loops and Conditional Statements에 대해 자세히 알아보기

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by