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I get this error:"This system does not seem to be linear."

조회 수: 2 (최근 30일)
Arda Nova
Arda Nova 2019년 1월 3일
댓글: Arda Nova 2019년 1월 4일
When I try this code for simple pendulum, I get results:
syms pt(t) th(t)
m=1; l=0.5; g=9.81;
e1= diff(th)*(m*l^2)==pt;
e2= diff(pt)==-m*g*l*sin(th);
vars = [pt(t); th(t)];
V = odeToVectorField([e1,e2]);
M = matlabFunction(V, 'vars', {'t','Y'});
interval = [0 5];
y0 = [0; pi/4];
ySol = ode45(M,interval,y0);
tValues = linspace(interval(1),interval(2),1000);
a= deval(ySol,tValues,1)/(m*l^2);
plot(tValues,a)
But when I use it for triple pendulum, it gives error. Couldn't solve it. Sorry if it's simple to figure out. Really new here.
syms theta1(t) theta2(t) theta3(t) p1(t) p2(t) p3(t)
m1=1; m2=1; m3=1; l1=1; l2=1;
l3=1; g=9.81; tau1=0; tau2=0; tau3=0;
I1=0; I2=0; I3=0;
e1= diff(theta1)*(I1+(m1+m2+m3)*l1^2)...
+diff(theta2)*(m2+m3)*l1*l2*cos(theta1-theta2)+...
diff(theta3)*m3*l1*l3*cos(theta1-theta3)==p1;
e2= diff(theta1)*(m2+m3)*l1*l2*cos(theta1-theta2)+...
diff(theta2)*(I2+(m2+m3)*l2^2)+...
diff(theta3)*m3*l2*l3*cos(theta2-theta3)==p2;
e3= diff(theta1)*m3*l1*l3*cos(theta1-theta3)+...
diff(theta2)*m3*l2*l3*cos(theta2-theta3)+...
diff(theta3)*(I3+m3*l3^2)==p3;
e4= diff(p1)== tau1-tau2-(m2+m3)*diff(theta1)*diff(theta2)*sin(theta1-theta2)...
-m3*diff(theta1)*diff(theta3)*l1*l3*sin(theta1-theta3)...
-(m1+m2+m3)*g*l1*cos(theta1);
e5= diff(p2)==tau2-tau3+(m2+m3)*diff(theta1)*theta2*l1*l2*sin(theta1-theta2)...
-m3*diff(theta2)*diff(theta3)*l2*l3*sin(theta2-theta3)...
-(m2+m3)*g*l2*cos(theta2);
e6= diff(p3)==tau3+(m3)*diff(theta1)*diff(theta3)*l1*l3*sin(theta1-theta3)...
+m3*diff(theta2)*diff(theta3)*l2*l3*sin(theta2-theta3)...
-m3*g*l3*cos(theta3);
vars= [theta1(t);theta2(t);theta3(t);p1(t);p2(t);p3(t)];
V = odeToVectorField([e1,e2,e3,e4,e5,e6]);
M = matlabFunction(V,'vars', {'t','Y'});
I have get that error in simple pendulum too, it was pt==diff(th)*(m*l^2), then I put the pt to the end, and it's solved. In triple pendulum I tried leaving diff(theta1) alone didn't work, tried to this code too, but nothing changed. Original equations are:
Adsız1.png
Adsız2.png

채택된 답변

Torsten
Torsten 2019년 1월 4일
The product of differentials in your equations (diff(theta1)*diff(theta3), e.g.) makes it impossible to use ODE45.
I don't know if it can be applied directly, but ODE15I is the correct solver to use in this case.
Best wishes
Torsten.
  댓글 수: 4
Torsten
Torsten 2019년 1월 4일
function main
y0 = [pi/2; pi/2; pi/2; 0; 0; 0];
yp0=[0; 0; 0; 0; 0; 0;];
[y0,yp0] = decic(@odennotfunatall,0,y0,[pi/2 pi/2 pi/2 0 0 0],yp0,[]);
[t,y] = ode15i(@odennotfunatall,[0 5],y0,yp0);
plot(t,y)
end
function hell2 = odennotfunatall(~,y,yp)
m1=1; m2=1; m3=1; l1=1; l2=1;
l3=1; g=9.81; tau1=0; tau2=0; tau3=0; I1=0; I2=0; I3=0;
hell2=zeros(6,1);
hell2(1)=yp(1)*(I1+(m1+m2+m3)*l1^2)...
+yp(2)*(m2+m3)*l1*l2*cos(y(1)-y(2))+...
yp(3)*m3*l1*l3*cos(y(1)-y(3))-y(4);
hell2(2)=yp(1)*(m2+m3)*l1*l2*cos(y(1)-y(2))+...
yp(2)*(I2+(m2+m3)*l2^2)+...
yp(3)*m3*l2*l3*cos(y(2)-y(3))-y(5);
hell2(3)=yp(1)*m3*l1*l3*cos(y(1)-y(3))+...
yp(2)*m3*l2*l3*cos(y(2)-y(3))+...
yp(3)*(I3+m3*l3^2)-y(6);
hell2(4)=-yp(4)+tau1-tau2-(m2+m3)*yp(1)*yp(2)*sin(y(1)-y(2))...
-m3*yp(1)*yp(3)*l1*l3*sin(y(1)-y(3))...
-(m1+m2+m3)*g*l1*cos(y(1));
hell2(5)=-yp(5)+tau2-tau3+(m2+m3)*yp(1)*yp(2)*l1*l2*sin(y(1)-y(2))...
-m3*yp(2)*yp(3)*l2*l3*sin(y(2)-y(3))...
-(m2+m3)*g*l2*cos(y(2));
hell2(6)=-yp(6)+tau3+(m3)*yp(1)*yp(3)*l1*l3*sin(y(1)-y(3))...
+m3*yp(2)*yp(3)*l2*l3*sin(y(2)-y(3))...
-m3*g*l3*cos(y(3));
end
Arda Nova
Arda Nova 2019년 1월 4일
Yeah the zeros, couldn't find a way to put it, thank you very much.

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추가 답변 (1개)

madhan ravi
madhan ravi 2019년 1월 3일
Just follow the same way showed in your previous question?
  댓글 수: 3
madhan ravi
madhan ravi 2019년 1월 3일
No problem , please recheck your equations take your time there are only four equations whereas you have 6 equations in your code.
Arda Nova
Arda Nova 2019년 1월 3일
Oh sorry, upper picture is streched out. At the right of "(60)" (on the picture), there is two more equations.

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