I have only two matrices A=[1,2 4; 2, 3, 4; 1, 2,3] and B=[1,2 4; 1, 2,3] in my hands. I want to solve the following problem.
where ,
such that
,
.
Please help me in providing the complete program.
Once it is computed, then I can use ''for loop'' for computing min for all rows of A and then max.
Thanks for sparing time.

댓글 수: 4

Rik
Rik 2018년 12월 26일
Related to this question?
Sultan
Sultan 2018년 12월 26일
Rik Wisselink yes. Since people are confused about the question so I have reframed here.
I am still waiting for a solution.
Can anyone provide the program please?
Thanks!
Image Analyst
Image Analyst 2018년 12월 26일
What is allowed to change? Lambda1 and lambda2? Is there some clever method you have heard of? Of course we could do it numerically with a simple brute force iteration over all possible values of lambda1 and lambda2. Would that be good enough?
Walter Roberson
Walter Roberson 2018년 12월 26일
We are not likely to give you complete code. If you show your code and your error message then we will help you debug.

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Sultan
Sultan 2019년 1월 15일
편집: Sultan 2019년 1월 15일

0 개 추천

Is it correct code for the above problem? In place of λ, I have used x.
A = [1 2 4; 2 3 4; 1 2 3]; B = [1 2 4; 1 2 3]
%Given: A; B;
%A = load('matrixA');
%B = load('matrixB');
n = length(B);
C = B';
D = ones(1,n);
for i = 1:length(A)
cvx_begin
variable x(n)
minimize( norm(A(i,:)' - C*x, 2))
subject to
D * x == 1
0 <= x <= 1
cvx_end
optimalValue(i) = cvx_optval^2;
X(:,i) = x;
end
maximumValue = max(optimalValue);
We can also use lsqlin. Thanks everyone for helping me.

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질문:

2018년 12월 26일

편집:

2019년 1월 15일

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