How do I keep consecutive number in a matrix?

For a matrix A,

A = [1 1 0 0 1 1 0 0;
    1 0 0 0 1 1 0 0;
    0 1 0 0 1 1 0 0]

I am trying to get B. How do I make it？

B = [1 1 0 0 0 0 0 0;
    1 0 0 0 0 0 0 0;
    0 0 0 0 0 0 0 0]

If the 1st number of a row is 1,

then the 1st sequence of consecutive 1 is kept and the rest numbers in that row turn 0.

i.e., A(1,:) -> B(1,:), A(2,:) -> B(2,:)

If the 1st number of a row is 0,

then all numbers in that row turn 0.

i.e., A(3,:) -> B(3,:)

Answer 1

[Matt J]

B=cummin(A,2);

[Image Analyst]

Clever. I didn't know about this function. +1 vote.

[Linjun He]

Cool!