We have circuit RLC.
g=Um.e^(-L/R t).cos⁡(2π/T t+φ)
Ecos(wt)
///////////////
This is our code:
w=2*pi*50;
E=5;
l=100e-6;
c=200e-6;
R=10;
t=0:0.01:300;
s=l/R;
T=2*pi*sqrt(l*c);
q=1/c*w;
v=(tan((l*w-q)/R))^-1;
g=E*cos(w*t)*exp(-s*t)*cos((2*pi/T)+v);
plot(t,g)
........
Error in Untitled (line 11)
g=E*cos(w*t)*exp(-s*t)*cos((2*pi/T)+v);

 채택된 답변

madhan ravi
madhan ravi 2018년 12월 24일
편집: madhan ravi 2018년 12월 24일

0 개 추천

w=2*pi*50;
E=5;
l=100e-6;
c=200e-6;
R=10;
t=0:0.01:300;
s=l/R;
T=2*pi*sqrt(l*c);
q=1/c*w;
v=(tan((l*w-q)/R))^-1;
g=E.*cos(w.*t).*exp(-s.*t).*cos((2.*pi./T)+v); % dots between operators (element-wise operation)
plot(t,g)
xlim([0 1]) % reduce the axis limit since it's stuffed so close
Screen Shot 2018-12-24 at 9.26.50 PM.png

추가 답변 (2개)

Image Analyst
Image Analyst 2018년 12월 24일

0 개 추천

This "works"
w=2*pi*50;
E=5;
l=100e-6;
c=200e-6;
R=10;
t = 0:0.01:300;
s=l/R;
T=2*pi*sqrt(l*c);
q=1/c*w;
v=(tan((l*w-q)/R))^-1;
g=E*cos(w*t) .* exp(-s*t) .*cos((2*pi/T)+v);
plot(t,g)
caption = sprintf('Plot of %d points', length(t));
title(caption, 'FontSize', 20);
Though with 30,0001 points, and a monitor that is only 1980 pixels across, the plot looks solid. If you reduce the number of points, you'll see something but it won't be the original signal - it will be a subsampled version and could be very deceptive to look at that and think that is what the curve looks like for an infinite number of points.
0001 Screenshot.png

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