Checking/Counting values in a given Timewindow

In the following Matrix I have the following '1' states according to their positions:

1	1174	1175	2006	2007	2809	2810	3670	3671	4541	4542	5265	5266	6139	6140	6584	6585	6856	6857	7646	7647	8382	8383	9142	9143
1	1	1	1	1	1	1	1	1	1	1	1	1	1	1	1	1	1	1	1	1	1	1	1	1

However, I have certain Timewindows for example:

1280,5 2560,5	3840,5

Now I want to check how many 1's are within this Time Window (1280,5 - 3840,5)

How can I do this?

Answer 1

[TADA]

I'm not sure what the ",5" stand for in your time frame, but you can do something like that:

states = [1 1174 1175 2006 2007 2809 2810 3670 3671 4541 4542 5265 5266 6139 6140 6584 6585 6856 6857 7646 7647 8382 8383 9142 9143;
          1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1];

% define time window
tw = [1280, 3840];

% if the '1' states are either 1 or 0 you can sum them up like that:
numOnes = sum(states(2, states(1,:) >= tw(1) & states(1,:) <= tw(2)))

    numOnes = 
    
         6

% otherwise, you can count the ones more specifically:
numOnes = sum(states(2, states(1,:) >= tw(1) & states(1,:) <= tw(2)) == 1)

    numOnes = 
    
         6

Answer 2

[GT]

Hi JamJan,

If I understand correctly you have a matrix with 2 rows, the first row shows times, and the second 1. You are asking to count how many ones between a certain time range.

Here is an example on how to do this: (where I am using larger than 6, and smaller than 23)

a = [ 1:4:40; ones(1,10)]
idx = a(1,:)>6 & a(1,:)<23
sum(a(2,idx))

This uses logical indexing.

I hope this makes sense to you and you can apply this to your case.