Unusual NaN appearing from a loop
조회 수: 2 (최근 30일)
이전 댓글 표시
Hi there.
I've been trying to run a loop to calculate the quartiles for each of the four columns in a dataset. The loop is as given below:
sized = size(data);
for i = 1:4
Minimum(i,1) = min(data(:,i));
Quart2(i,1) = median(data(:,i));
if rem(sized(1),2) == 0
Quart1(i,1) = median(data(data(:,1) < Quart2(i,1)));
Quart3(i,1) = median(data(Quart2(i,1) < data(:,i)));
else
Quart1(i,1) = median(Minimum(i,1): Quart2(i,1));
Quart3(i,1) = median((Quart2(i,1)):(max(data(:,i))));
end
Maximum(i,1) = max(data(:,i));
end
I'm generating a table of these results after the loop and I get something like this once I run the script:
The problem with this is that I don't know why the 'NaN' values appear here. When I run the line of code evaluating 'Quart1' independently in the command window for this very dataset, it gives me the correct value of 0. I'd be really grateful if someone could help me with this.
Thanks!
댓글 수: 0
답변 (1개)
OCDER
2018년 12월 3일
It seems that you are taking the median of an empty number
%EXAMPLE
data = [1 2 3];
Quart2 = 4;
Quart1 = median(data(Quart2 < data));
Quart1 =
NaN
Double check that there is no empty values. Otherwise, replace NaN's with 0's.
댓글 수: 2
OCDER
2018년 12월 3일
When you do the logical index:
Quart2(i,1) < data(:,i)
It's possible that NO DATA agrees with this condition. So when you do this:
data(Quart2(i,1) < data(:,i)),
you get NO DATA, or an empty array, []. That's equivalent to doing this:
Quart1 = median([]) = NaN.
To fix, do this:
Quart1(isnan(Quart1)) = 0;
참고 항목
카테고리
Help Center 및 File Exchange에서 NaNs에 대해 자세히 알아보기
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!