Want to create colors depending on the number of columns i got in my X

Hello, i want to plot each column, and i want to associate each column with a color but automaticly.

X = [1:26]';
Y = [1:26]';
[n,m] = size(X);
rows = 3;
columns = ceil(n/rows);
extra_row = columns * rows;
X(n+1:extra_row) = NaN;
X_new = reshape(X,rows,columns)

So, if i put a different numbe ron "ROWS" my "X_NEW" will have more or less columns.

Question -> How to create a vector of colors or string of colors depending on the number of columns of X_new?

Thanks for your time

Answer 1

[Jan]

What about:

CMap = parula(rows)

[Tiago Dias]

Sorry, i made a loop for and i plot each j and solved my problem like that has maltab selects the colors he wants, tought i canceled this question since i found how to do it.

[Tiago Dias]

colormap winter % for example
for k = 1:10
    plot(X(:,k),Y(:,k),'*')
    hold on
end

This will give me 10 plots, each one with a different color, but the plot 8 or 9, it repeats the color from plot1, how can I change this with the color maps?

[Jan]

As I have suggested already:

CMap = winter(10);
for k = 1:10
    plot(1:10, rand(1,10), '*', 'Color', CMap(k, :));
    hold on
end
legend

There is no large difference in the 10 different colors of the winter color map, but at least the colors are not repeated.

[Tiago Dias]

oh ok. I place with a vector

plot(1:10, rand(1,10), '*', 'Color', [CMap(k,1) CMap(k,2) CMap(k,3)]);

thanks!

[Jan]

CMap(k, :) is the abbreviation for CMap(k, 1:3), which is exactly the same as [CMap(k,1) CMap(k,2) CMap(k,3)], so I'd prefer the leaner notation.