a=[2 3 2;3 3 3;4 4 4;2 5 4; 3 5 5; 4 4 4; 7 3 4]
how do I delete only those rows where elemets repeat for entire row length. In this example matrix, the three rows with all 3s and all 4s where this happens.

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Star Strider
Star Strider 2018년 11월 25일

1 개 추천

Try this:
a=[2 3 2;3 3 3;4 4 4;2 5 4; 3 5 5; 4 4 4; 7 3 4];
a_new = a(all(diff(a,[],2) ~= 0, 2),:)
If all the columns in a particular row are the same, the vector returned by the diff function will all be uniformly 0. The all function across rows (dimension = 2) detects that, and deletes those rows.
a =
2 3 2
3 3 3
4 4 4
2 5 4
3 5 5
4 4 4
7 3 4
a_new =
2 3 2
2 5 4
7 3 4

댓글 수: 3

klb
klb 2018년 11월 26일
i want only the row with all elements same to be eliminated. so n ,n, x >> keep but n, n ,n>> delete
klb
klb 2018년 11월 26일
ok i repalced 'all' with 'any' and that gives the requried answer. But thank you! Now on to researching the finess between all and any...
Star Strider
Star Strider 2018년 11월 26일
As always, my pleasure.

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Walter Roberson
Walter Roberson 2018년 11월 25일

0 개 추천

mask = all(diff(a, [], 2) == 0)
Now you can use mask as the row selector in deletion.

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klb
2018년 11월 25일

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2018년 11월 26일

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