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Need to use cellfun for returning index of array

조회 수: 4 (최근 30일)
Thulasi Durai Durai Samy
Thulasi Durai Durai Samy 2012년 7월 9일
Hello
I need to find index for string in structures when compare with required string.
I use the following code
for i=1:numel(LD)
if strcmp('Lam1',LD(i).Name)
break;
end
end
where i = array index.
Here I will find the index for string residing in LD(:).Names
is their any easy way to find the index using cellfun
I tried like this cellfun(@strcmp,'Lam1',LD(:).Names)
should return the index, correct me I am worng.
  댓글 수: 2
Jan
Jan 2012년 7월 9일
편집: Jan 2012년 7월 9일
You forgot to explain the type of LD.Name: Are they strings or cell strings? And btw., is it LD.Name or LD.Names in plural? I avoid corresponding programming errors by the simple convention:
  • All names in singular
  • When it matters if a variable is a scalar entity or a list of objects: aMyObject and MyObjectList.
I do not think that this is nicer, but avoiding sources of bugs is more important, especially because useful programs tend to grow.
Thulasi Durai Durai Samy
Thulasi Durai Durai Samy 2012년 7월 9일
thanks for your nice comments

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채택된 답변

Jan
Jan 2012년 7월 9일
편집: Jan 2012년 7월 9일
No need for cellfun or arrayfun:
index = find(strcmp('Lam1', {LD.Name}), 1);
{LD.Name} is efficient, because it creates shared data copies only - this means that the actual strings are not duplicated.
  댓글 수: 2
Thulasi Durai Durai Samy
Thulasi Durai Durai Samy 2012년 7월 9일
ya, it works !! what actually happening in side can you brief me. why to pass 1 as argument for 'find' function.
Jan
Jan 2012년 7월 9일
find(., 1) searchs for the first occurrence only, see help find. On one hand this is a little bit faster, if LD is really large. On the other hand it replicates the behaviour of your function, which breaks after the first occurence also.

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추가 답변 (2개)

F.
F. 2012년 7월 9일
try this :
regexp( { LD(:).Name } , 'Lam1' , 'once )
it's to find the first occurance of Lam1 in the cell array { LD(:).Name }

Walter Roberson
Walter Roberson 2012년 7월 9일
편집: Walter Roberson 2012년 7월 9일
cellfun(@(S) strcmp('Lam1',S), {LD.Name} )

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