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How to find the mode of a string array (no longer works in 2018b)

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Anil Kamath
Anil Kamath 2018년 11월 16일
댓글: hp 2021년 4월 1일
I have discovered that the following code worked in Matlab 2018a but now throws an error in 2018b:
mode(["A","A","B"],2)
It would appear that the new version of matlab only allows computing the mode on numeric arrays. Is this a bug, or a known change to how this function works (I know that in this version, some of these functions now operate on multiple dimensions now)? And is there a quick workaround? So far I've created the following hack to operate on strings, though I expect it's pretty inefficient:
Y = strings(1,size(X,2));
for n = 1:size(Y,2)
C = categorical(X(:,n));
CC = categories(C);
[~,ind] = max(countcats(C));
if ~isempty(ind)
Y(n)=string(CC(ind));
end
end

채택된 답변

Adam Danz
Adam Danz 2018년 11월 16일
편집: Adam Danz 2018년 11월 16일
The documentation for both 2018a and 2018b indicate that the first input to mode() "can be a numeric array, categorical array, datetime array, or duration array." One workaround would be to change your string to a categorical vector.
This works in 2018b
mode(categorical( ["A","A","B"]))
ans =
categorical
A
If needed, you could convert back to a string:
string(mode(categorical( ["A","A","B"])))
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추가 답변(1개)

Philip Borghesani
Philip Borghesani 2018년 11월 16일
Use a character vector instead of a string array:
mode(['A','A','B'],2)
% or
mode('AABBCCC',2)
I belive it was a bug that it worked with strings in R2018a. It has always worked with character vectors and sombody was a bit too helpful adding support for strings which can’t simply be treated as a numeric value.
  댓글 수: 1
Anil Kamath
Anil Kamath 2018년 11월 19일
I'm afraid this won't work in my use-case as it has to work on multi-character strings rather than just scalar chars (I put a simplified example in my initial question). Adam's answer above looks like it works.

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