How to remove a bracketed number from a cell array while leaving the number in front of it alone
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Hi, I have a cell array called "mycellarray" with the following types of strings in it: 24[13]
The [13] in this case is a reference to a footnote and I want to remove the [13] and just have the number 24 left. How do I use a regular expression to remove "[13]" or any footnote i.e. [3] from the number.
Example of the contents of the cell array
13.4[5]
24[11]
56.99[23]
22[4]
I want to remove all the bracketed values along with the number inside the brackets and just have the double number in front kept in the cell array Thank you for your help.. Bob
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madhan ravi
2018년 11월 11일
편집: madhan ravi
2018년 11월 11일
mycellarray={'24[13]'}
regexprep(mycellarray, '\[(.*?)\]', '$1') %edited after sir Walter's comment
or
A='13.4[5] 24[11] 56.99[23] 22[4]'
A(A=='[') = [];
% Remove any and all right brackets.
A(A==']') = []
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Walter Roberson
2018년 11월 11일
'\[(.*)\]' selects too much if there can be multiple matches in one string. '\[(.*?)\]' would be better.
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