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How can I match a string in a cell array and then pull out data from the row with the match?

조회 수: 4 (최근 30일)
Hello,
I have been struggling to solve this problem on my own after combing the internet for solutions. Here is my code below.
A = {'Red123' 'Bob' '08/11/2018' 'Blah'; 'Red456' 'Jim' '11/08/2018' 'Meh'; 'Blue123' 'Bean' '02/11/2018' 'MoreMeh';...
'Blue456' 'Dale' '05/05/2005' 'Nope'};
IDTag = 'Blue123';
check = strcmp(A,IDTag);
check returns a 4x4 logical array with a 1 where I would expect it. What I'd like to figure out how to do is to then take the data after the match in the row (in this case it would be A(3)). So I'd like to have my script find the match and then assign A(3,2) and A(3,3) to variables to be passed off elsewhere. How can I do this dynamically and autonomously so when I need to pass in variables to check this list, I can quickly match and pull out data?
To reiterate, I want to match on Blue123, and if it is a match, I want to assign 'Bean' and '02/11/2018' to two different variables for later use. If I later want to match a different IDTag, I want it to do the same thing.
Thank you!

채택된 답변

L
L 2018년 11월 8일
Go figure, a few minutes after posting the question I stumble across something elsewhere that helps me discover the answer I was looking for.
Solution to my question
[~ idx] = ismember(IDTag,A);
Name = B(idx,2);
Date = B(idx,3);
  댓글 수: 1
madhan ravi
madhan ravi 2018년 11월 8일
편집: madhan ravi 2018년 11월 8일
A small correction I suspect it should be
Name = A(idx,2);
Date = A(idx,3);
from the above details you provided in the question because B is not defined in the above

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추가 답변 (1개)

Nick
Nick 2018년 11월 8일
편집: Nick 2018년 11월 9일
For now i am assuming the ID is always in the first column. You could have the logical matrix repeat itself and then use that as an index:
% your code
A = {'Red123' 'Bob' '08/11/2018' 'Blah'; 'Red456' 'Jim' '11/08/2018' 'Meh'; 'Blue123' 'Bean' '02/11/2018' 'MoreMeh';...
'Blue456' 'Dale' '05/05/2005' 'Nope'};
IDTag = 'Blue123';
check = strcmp(A,IDTag);
% change the check matrix to have the entire row the same as the first row
check = repmat(check(:,1), 1, size(check,2));
correspondingData = A(check);
name = correspondingData{2};
date = correspondingData{3};
alternatively you can also do:
index = find(check(:,1)==1);
correspondingData = A(index,:);
name = correspondingData{2};
date = correspondingData{3};
  댓글 수: 2
L
L 2018년 11월 8일
Both above didn't work for me, but it could have been a misunderstanding in the question as the results I got from your code gave me the IDs and not the information I was looking for after those IDs when they match.
I did figure it out though, below is what I was looking for.
Nick
Nick 2018년 11월 9일
I just saw i made a mistake in the answer above (accidantly used A instead of correspondingData). Thats the reason it did not work, edited my answer to correct for this error. I'm glad you found a solution already.

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