Question about find function on matlab and

I am trying to use the find function to locate the index where x = 4 is located but every time I see the value its 401 can someone please because i dont understand this at all.

Answer 1

[Walter Roberson]

The output is correct.

The first x is 0. You increment by 0.01. So the N'th entry in x, x(N), contains (N-1)/100. Thus x(401) contains (401-1)/100 = 400/100 = 4.0. And that never changes.

Answer 2

[madhan ravi]

x0 = 4 %edited after sir Walter’s comment
y0 = interp1(x,y_linear,x0)

Now you will get the corresponding y value when x is 4.

[Walter Roberson]

y0 = 4
x0 = interp1(y_linear,x, y0)

[madhan ravi]

Ah thank you sir Walter :).

[Walter Roberson]

I suspect that the real question is to find x such that y is 4, which is what I coded for in my comment here.

[madhan ravi]

find function to locate the index where x = 4

I am not sure either sir from the above statement

Answer 3

[Eduardo Jimenez]

This result I am trying to get with my code

[Walter Roberson]

Okay, then, always getting 401 is correct for the location of 4.0 . For x = 6, it would come out as 601.

The point of the exercise is to not have to come up with the formula, to use find() to locate the value.