Output Array, how to assign values from a function
조회 수: 13 (최근 30일)
이전 댓글 표시
I'm new to coding so just assume I know next to nothing. I've created my code for an assignment and have what I want, I don't don't understand how to manipulate it. Here's the code:
function [f] = fibanotchy
f=zeros(100,2,'uint64');
format long g
f(1)=1
f(2)=1
for k=3:100
f(k)=f(k-2)+ f(k-1);
colNames = {'F','n'};
sTable = array2table(f,'VariableNames',colNames)
It's the output from running the function I don't understand. It loops through the index k and displays every iteration. I thought ; suppressed that? Second, I've allocated the f array for the 100 values and a second row. I want to change those zeros to each iteration of the function (which is n, or nth number in the sequence). I can't do it. I've tried to define n=1:100 and put it in the array and can't. It seems simple but nothing I've tried works. I'm not sure how to access the second column of the matrix and get what I want in there. Or maybe I'm looking at it wrong. I've looked at Tables and maybe that's how to code it, but I'm not sure.
댓글 수: 2
채택된 답변
madhan ravi
2018년 10월 28일
편집: madhan ravi
2018년 10월 28일
fibanotchy
function [f] = fibanotchy
f=zeros(100,2,'uint64');
format long g
f(1)=1
f(2)=1
n=input('nth term ? ')
for k=3:n
f(k,1)=f(k-2)+ f(k-1);
f(k,2) = k;
end
f(1,2) =1;
f(2,2)=2;
end
댓글 수: 3
madhan ravi
2018년 10월 28일
Exactly you are getting the idea . And I defined f(1,2) as 1 and f(2,2) as 2 because the loop starts from 3 .
추가 답변 (0개)
참고 항목
카테고리
Help Center 및 File Exchange에서 Matrix Indexing에 대해 자세히 알아보기
제품
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!