Use MATLAB built-in function conv() to compute and plot y[n]

my code is: clear all; close all; clc;

%first sequence x=[0, 1, 1, 1, 0, 0, 0]; %second sequence h=[1, 2, 4, 8, 16, 32, 64];

%built-in function

y= conv(x,h); disp('The convolution output is'); disp(y); and the command window is: >> k=[0, 1, 1, 1, 0, 0, 0]; >> >> y=[1, 2, 4, 8, 16, 32, 64]; >> >> z= conv(k,y); >> >> disp(z) 0 1 3 7 14 28 56 112 96 64 0 0 0

>> subplot(6,1,1);plot(k);subplot(6,1,2);plot(y);subplot(6,1,3);plot(z); >> subplot(6,1,1);stem(k);subplot(6,1,2);stem(y);subplot(6,1,3);stem(z); My problem is that the figure "欲2" where I make the code doesn't match the figure "欲" which the question gives. I have no idea if my code and the final figure"欲2" is right.

[madhan ravi]

attach correct figure2 and the wrong figure2

[CHENG-YI LI]

the figure I get

[CHENG-YI LI]

the figure question gives

[CHENG-YI LI]

May you help me solve the problem?

[Image Analyst]

Answer 1

[Bruno Luong]

I don't see what is the difficulty for you.

MATLAB array is 1-indexing, and CONV just do the work on array indices.

If you know the correspondence between indices and the [n] value, which obviously 0-base, therefore equal to (matlab indices-1), just shift the indices and plot with 2 arguments.

x = ...
h = ...
y = conv(x,h);

subplot(3,1,1);
stem(0:length(x)-1,x);

subplot(3,1,2);
stem(0:length(h)-1,h)

subplot(3,1,3);
stem(0:length(y)-1,y)

Answer 2

[asad ali]

x = ...

h = ...

y = conv(x,h);

subplot(3,1,1);

stem(0:length(x)-1,x);

subplot(3,1,2);

stem(0:length(h)-1,h)

subplot(3,1,3);

stem(0:length(y)-1,y)