Is there a way to index a variable to a certain position in the array

I have some code that looks like this:

if n==1
  for i=1:size(ob,1)
    rt(i,:,:)=radon(squeeze(ob(i,:,:)),ra);
  end
elseif n==2
  for i=1:size(ob,2)
    rt(i,:,:)=radon(squeeze(ob(:,i,:)),ra);
  end
elseif n==3
  for i=1:size(ob,3)
    rt(i,:,:)=radon(squeeze(ob(:,:,i)),ra);
  end
end

Is there a way to get the i variable to the nth position of the ob matrix so that I don't have to write an if statement for each n?

[madhan ravi]

variable you mean n??

Answer 1

[Fangjun Jiang]

Depending on the value of n, you want to loop through the different dimension of matrix.

I think you can utilize the function shiftdim() to pre-process you matrix and then do the same loop, something like

shiftdim(ob,n)

Answer 2

[Jose Sanchez]

This should work:

n=3; % or set n=1 or n=2
tmp = permute(ob, [setdiff(1:3,n) n]);
for i=1:size(tmp,3)
    rt(i,:,:) = radon(tmp(:,:,i),ra);
end

[Fangjun Jiang]

+1, this approach should work too.