Code for equation with ln
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How can i Code it?
u=0.23 y=0.3 v=0.00001
u/u’=5*log(u’*y/v)-3.05
u’=?
I need to find the value of u’.
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답변 (1개)
Star Strider
2018년 10월 21일
Try this:
u=0.23;
y=0.3;
v=0.00001;
fcn = @(ustar,u,y,nu) 5*log(ustar.*y/nu)- 3.05 - u/ustar;
ustar = fsolve(@(ustar)fcn(ustar,u,y,v), 1)
ustar =
0.00918407730971717
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Star Strider
2018년 10월 21일
I already posted all the code that is needed to solve this problem.
You need to have the Optimization Toolbox installed to use fsolve.
You will have fminsearch regardless, so try using fminsearch on the norm of ‘fcn’:
ustar = fminsearch(@(ustar)norm(fcn(ustar,u,y,v)), 1)
ustar =
0.00918426513671787
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