Hi,
I have this table-type data
tdata.yearID=[1950;1950;1950;1951;1951;1951;1951;1952;1952;1952];
tdata.cluster=[1;3;4;1;2;3;4;1;2;3];
tdata.GroupCount=[5;2;6;2;2;4;2;1;2;2];
tdata= struct2table( tdata)
tdata =
10×3 table
yearID cluster GroupCount
______ _______ __________
1950 1 5
1950 3 2
1950 4 6
1951 1 2
1951 2 2
1951 3 4
1951 4 2
1952 1 1
1952 2 2
1952 3 2
Currently I am using this code below to do pivot, but it was very slow for large data. Is there a way to vectorize this code?
[uniqYr, ~, JYr]= unique( tdata.yearID);
nEventData.yearID= [1: 2000]';
[ nEventData.cnt]= zeros( length(nEventData.yearID), 4);
for runYr= 1: length( uniqYr)
indxYr= uniqYr( runYr);
tloc = (JYr== runYr);
tt = tdata( tloc, :);
nEventData.cnt( indxYr, tt.cluster')= tt.GroupCount';
end % for runYr
So results look like this for rows 1949-1955. Other rows have zeros.
nEventData.cnt (1949:1955,:)
ans =
0 0 0 0
5 0 2 6
2 2 4 2
1 2 2 0
0 0 0 0
0 0 0 0
0 0 0 0

댓글 수: 2

Peter Perkins
Peter Perkins 2018년 10월 5일
Pete, your code does not run and it's not at all clear what you want as your result. You are going to need to be much more clear.
Peter Perkins
Peter Perkins 2018년 10월 5일
The updated question and output clarify that unstack does what you need, as Steve suggests.

댓글을 달려면 로그인하십시오.

 채택된 답변

Steven Lord
Steven Lord 2018년 10월 5일

1 개 추천

The output you described looks somewhat like the first example in the documentation for the unstack function. I think what you want is something close to the pivotedTdata variable created by this example:
tdata.yearID=[1950;1950;1950;1951;1951;1951;1951;1952;1952;1952];
tdata.cluster=[1;3;4;1;2;3;4;1;2;3];
tdata.GroupCount=[5;2;6;2;2;4;2;1;2;2];
tdata= struct2table( tdata)
pivotedTdata = unstack(tdata, 'GroupCount', 'cluster')
You can retrieve data for a particular year this way:
pivotedTdata(pivotedTdata.yearID == 1950, :)

추가 답변 (1개)

Lola Davidson
Lola Davidson 2023년 3월 17일

3 개 추천

As of R2023a, you can also use the pivot function.
pivotedTable = pivot(tdata, Rows="yearID", Columns="cluster", DataVariable="GroupCount");

카테고리

도움말 센터File Exchange에서 Logical에 대해 자세히 알아보기

질문:

2018년 10월 4일

답변:

2023년 3월 17일

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by