So I have a value 'r' that I'm trying to change from a constant (r=5) to time-dependent (r=1.5*t) when I call a function and redefine 'r'. So far, no luck, I'm new at MATLAB and still don't know a lot of syntax. Here's one of my attempts (the third plot has the changing r):
%function file:
function ydot = ode5_39 (t,y,r)
r=5;
L = 1;
g = 9.81;
ydot(1) = y(2);
ydot(2) = (1/L)*(r*cos(y(1))-g*sin(y(1)));
ydot=ydot';
%plot file:
[t,y,r]=ode45('ode5_39', [0 10], [0.5 0]);
subplot(3,1,1);
plot(t,y(:,1));
ylim([-0.5 1]);
hold on
plot(t,y(:,2));
title('part (a)')
legend('x','xdot');
[t,y,r]=ode45('ode5_39', [0 10], [3 0]);
subplot(3,1,2);
plot(t,y(:,1));
hold on
plot(t,y(:,2));
title('part (b)')
legend('x','xdot');
[t,y,r]=ode45('ode5_39', [0 10], [3 0]);
r=1.5*t;
subplot(3,1,3);
plot(t,y(:,1));
hold on
plot(t,y(:,2));
title('part (c)')
legend('x','xdot');

댓글 수: 1

You assigned r=5 within the function, also you listed r in the function inputs lists, why??

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 채택된 답변

Walter Roberson
Walter Roberson 2018년 10월 2일

0 개 추천

function ydot = ode5_39 (t, y, rf, rc)
r = rf*t + rc;
L = 1;
g = 9.81;
ydot(1) = y(2);
ydot(2) = (1/L)*(r*cos(y(1))-g*sin(y(1)));
ydot=ydot';
with
[t, y] = ode45(@(t,y) ode5_39(t, y, 0, 5), [0 10], [0.5 0]); %r = 0*t + 5
and
[t, y] = ode45(@(t,y) ode5_39(t, y, 1.5, 0), [0 10], [3 0]); %r = 1.5*t + 0
If you wanted something more complicated than linear for finding r, then probably the easiest way to do that would be to use an anonymous function. No point in describing that unless you need it, though.

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도움말 센터File Exchange에서 Creating and Concatenating Matrices에 대해 자세히 알아보기

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2018년 10월 2일

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2018년 10월 2일

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