cftool and fit function returns different results

조회 수: 2 (최근 30일)
yonatan s
yonatan s 2018년 9월 27일
편집: dpb 2018년 9월 27일
I fit data using both methods and am getting different results.
The fitted function is: f(x)=a*x^(b).
The results are:
cftool: a=3.238e+10, b=-1.573.
fit function: a=1.516e+07, b=-1.111.
And of course, the goodness of fit parameters are different.
I set the options in the fit function to be the same as in cftool.
The script:
PowerEqn='a*x^(b)';
fo = fitoptions('Method','NonlinearLeastSquares',...
'Robust','off',...
'Algorithm','Trust-Region',...
'DiffMinChange',1e-8,...
'DiffMaxChange',.1,...
'MaxFunEvals',600,...
'MaxIter',400,...
'TolFun',1e-6,...
'TolX',1e-6,...
'StartPoint',[x(1),y(1)]);
ft=fittype(PowerEqn,'options',fo);
[f,stat]=fit(x',y',ft);
The Data:
x=[1.5804e+07,1.1580e+08,2.1580e+08,3.1580e+08,4.1580e+08,5.1580e+08,6.1580e+08,7.1580e+08,
8.1580e+08,9.1580e+08,1.0158e+09,1.1158e+09,1.2158e+09,1.3158e+09,1.4158e+09];
y=[1.5398e-01,4.7623e-03,6.6259e-03,1.7019e-03,1.4101e-03,0,5.8168e-06,
0,0,0,0,0,0,0,0]
  댓글 수: 3
yonatan s
yonatan s 2018년 9월 27일
편집: yonatan s 2018년 9월 27일
yeah you're right. but in cftool I pressed on FitOptions button (see image) and just entered those results. so what am I missing?
dpb
dpb 2018년 9월 27일
편집: dpb 2018년 9월 27일
Your starting points aren't the same as in the cftool window -- if I use the builtin form of the equation I get the default result.
However using the text form for the equation and the [x(1) y(1)] startpoints then I get your same result. So, there's something going on behind the scenes...
>> fit(x',y','power1',fo)
ans =
General model Power1:
ans(x) = a*x^b
Coefficients (with 95% confidence bounds):
a = 3.231e+10 (-6.071e+10, 1.253e+11)
b = -1.573 (-1.746, -1.399)
>> fo.StartPoint=[x(1) y(1)];
>> fit(x',y','power1',fo)
ans =
General model Power1:
ans(x) = a*x^b
Coefficients (with 95% confidence bounds):
a = 3.276e+10 (-6.174e+10, 1.273e+11)
b = -1.574 (-1.748, -1.4)
>> eqn='a*x^b';
>> fit(x',y',eqn,fo)
ans =
General model:
ans(x) = a*x^b
Coefficients (with 95% confidence bounds):
a = 1.58e+07 (-2.917e+07, 6.077e+07)
b = -1.114 (-1.285, -0.9424)
>> fo.StartPoint=[8.2638E11 -1.7388];
>> fit(x',y',eqn,fo)
ans =
General model:
ans(x) = a*x^b
Coefficients (with 95% confidence bounds):
a = 8.264e+11 (-3.335e+12, 4.988e+12)
b = -1.768 (-2.072, -1.464)
>>
What, specifically, I've no klew

댓글을 달려면 로그인하십시오.

답변 (0개)

카테고리

Help CenterFile Exchange에서 Get Started with Curve Fitting Toolbox에 대해 자세히 알아보기

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by