I've come across an unexpected result. Symbolic equation substitution is yielding wrong result. Below is my code.I've tried reset(symengine) but it doesen't seem to help.
syms y real
Tsym = ...
(204800*y)/7 - (19342813113834066795298816*y^2)/661131307601750375 + 60;
Tfunc=@(y) ...
(204800*y)/7 - (19342813113834066795298816*y^2)/661131307601750375 + 60;
H=0.0005;
y=H;
symval=subs(Tsym);
funcval=Tfunc(H);
if funcval~=symval
fprintf('Something is wrong. \n')
end

답변 (1개)

Bish Erbas
Bish Erbas 2018년 9월 25일

0 개 추천

Code below works for me. You defined the H and y variables after defining the symbolic equations. Move the variable definition at the beginning of your code.
syms y real
H=0.0005;
y=H;
Tsym = ...
(204800*y)/7 - (19342813113834066795298816*y^2)/661131307601750375 + 60;
Tfunc=@(y) ...
(204800*y)/7 - (19342813113834066795298816*y^2)/661131307601750375 + 60;
symval=subs(Tsym);
funcval=Tfunc(H);
if funcval~=symval
fprintf('Something is wrong. \n')
end

댓글 수: 1

Hey there Bish! It seems your solution does return the correct value. However, I lose the symbolic function in the process. Tsymb (the equation is now equal to a value, not an equation). What's the best practice to use subs if I want to continue evaluating the same function for N values of y?

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2018년 9월 25일

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