Poisson solver for background oriented schlieren

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abdelhafidh moumen
abdelhafidh moumen 2018년 9월 9일
편집: abdelhafidh moumen 2018년 9월 10일
Hi, I'm trying to construct the density field from an optical method called Background oriented schlieren: so from two displacement matrix ux and uy i'm creating the rhs of the poisson eq : Nxx+Nyy=K*rhs the result that i'm getting is not what i'm supposed to get, could any one spot the errors in point of view image analysis and poisson solver
if true
clear all
close all
ux1=load('bos\ux_pixi2_bos');
ux=ux1.ux;
uy1=load('bos\uy_pixi2_bos');
uy=uy1.uy;
%%camera parameters and fov
coe_n= -2.911e-04%mm^-2
b_fld=0.1233; %mm
b_brd=0.1983;%mm
M=0.1983;%mm/pixel
ux=M.*ux;%mm
uy=M.*uy;%mm
% create the RHS element
% Preallocation for the variables du and duy;
[width,height]=size(ux);
dux=zeros(width,height);
duy=zeros(width,height);
%%Compute the central differences
for k=2:width-1
for j=2:height-1
dux(k,j)=(ux(k+1,j)-ux(k-1,j))/2*b_brd;
duy(k,j)=(uy(k,j+1)-uy(k,j-1))/2*b_brd;
end
end
rhs=dux+duy;
rhs(isnan(rhs)) = 0 ;
b=(coe_n).*(rhs);
%%Specifying parametersfor poisson solver
[Nx,Ny]=size(rhs);
%%Initial Conditions
pn=1.1.*ones(Nx,Ny); %Preallocating pn
i=2:Nx-1;
j=2:Ny-1;
% Poisson equation solution (iterative) method
tol = 1e-20; % Set tollerance
maxerr = 1; % initial error
iter = 0;
p=pn;
while maxerr > tol
iter = iter + 1;
% Dirichlet BC
p(1,:)=1.000227;
p(:,Ny)=1.000277;
p(:,1)=1.000227;
for j = 2:Ny-1
for i = 2:Nx-1
p(i,j)=0.25*(double(pn(i+1,j))...
+double(p(i-1,j))...
+double(pn(i,j+1))...
+double(p(i,j-1))-double(b(i,j)*(b_fld^2)));
end
%%Neuman boundary condition along the bottom wall for
p(Nx,j)=1/4*(2*pn(Nx-1,j)+pn(Nx,j+1)+pn(Nx,j-1)-((b_fld^2)*b(Nx,j)));
end
maxerr =sqrt(sum(sum((p-pn).^2)));
disp(['Maximum error is ',num2str(maxerr),'Iteration no. ',num2str(iter)]);
% update pn
pn=double(p);
end
regards

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