Whats wrong with this command?

조회 수: 16 (최근 30일)
Natalio Ramirez
Natalio Ramirez 2018년 9월 6일
편집: Walter Roberson 2020년 4월 2일
Im trying to enter this equation which I will then use on a function I created.
y = @m sqrt(9.81*m/0.25)*tanh(sqrt(9.81*0.25/m)*4)-36;
y = @m sqrt(9.81*m/0.25)*tanh(sqrt(9.81*0.25/m)*4)-36;
Error: Invalid expression. Check for missing multiplication operator, missing or unbalanced
delimiters, or other syntax error. To construct matrices, use brackets instead of parentheses.

채택된 답변

madhan ravi
madhan ravi 2018년 9월 6일
편집: madhan ravi 2018년 9월 6일
Use function handle correctly:
y = @(m) sqrt(9.81*m/0.25)*tanh(sqrt(9.81*0.25/m)*4)-36;
  댓글 수: 2
Natalio Ramirez
Natalio Ramirez 2018년 9월 6일
Can u elaborate on ur answer. I only used y = @m sqrt(9.81*m/0.25)*tanh(sqrt(9.81*0.25/m)*4)-36; And still got the error
madhan ravi
madhan ravi 2018년 9월 6일
편집: madhan ravi 2018년 9월 6일
you should use @(m) with parenthesis instead of just @m

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추가 답변 (1개)

Lesley Duwa
Lesley Duwa 2020년 4월 2일
편집: Walter Roberson 2020년 4월 2일
%values are in pu;
Pm = Generator active power ouptut;
E = 1.25;
V = infinite bus voltage;
X1 = pre-fault reactance;
X2 = during-fault reactance;
X3 = post-fault reactance;
if exist('Pm')~=1
Pm = input('Generator output power in p.u. Pm = '); else, end
if exist('E')~=1
E = input('Generator e.m.f. in p.u. E = '); else, end
if exist('V')~=1
V = input('Infinite bus-bar voltage in p.u. V = '); else, end
if exist('X1')~=1
X1 = input('Reactance before Fault in p.u. X1 = '); else, end
if exist('X2')~=1
X2 = input('Reactance during Fault in p.u. X2 = '); else, end
if exist('X3')~=1
X3 = input('Reactance aftere Fault in p.u. X3 = '); else, end
Pe1max = E*V/X1; Pe2max=E*V/X2; Pe3max=E*V/X3;
delta = 0:.01:pi;
Pe1 = Pe1max*sin(delta); Pe2 = Pe2max*sin(delta); Pe3 = Pe3max*sin(delta);
d0 =asin(Pm/Pe1max); dmax = pi-asin(Pm/Pe3max);
cosdc = (Pm*(dmax-d0)+Pe3max*cos(dmax)-Pe2max*cos(d0))/(Pe3max-Pe2max);
if abs(cosdc) > 1
fprintf('No critical clearing angle could be found.\n')
fprintf('system can remain stable during this disturbance.\n\n')
return
else, end
dc=acos(cosdc);
if dc > dmax
fprintf('No critical clearing angle could be found.\n')
fprintf('System can remain stable during this disturbance.\n\n')
return
else, end
Pmx=[0 pi-d0]*180/pi; Pmy=[Pm Pm];
x0=[d0 d0]*180/pi; y0=[0 Pm]; xc=[dc dc]*180/pi; yc=[0 Pe3max*sin(dc)];
xm=[dmax dmax]*180/pi; ym=[0 Pe3max*sin(dmax)];
d0=d0*180/pi; dmax=dmax*180/pi; dc=dc*180/pi;
x=(d0:.1:dc);
y=Pe2max*sin(x*pi/180);
y1=Pe2max*sin(d0*pi/180);
y2=Pe2max*sin(dc*pi/180);
x=[d0 x dc];
y=[Pm y Pm];
xx=dc:.1:dmax;
h=Pe3max*sin(xx*pi/180);
xx=[dc xx dmax];
hh=[Pm h Pm];
delta=delta*180/pi;
if X2 == inf
fprintf('\nFor this case tc can be found from analytical formula. \n')
H=input('To find tc enter Inertia Constant H, (or 0 to skip) H = ');
if H ~= 0
d0r=d0*pi/180; dcr=dc*pi/180;
tc = sqrt(2*H*(dcr-d0r)/(pi*50*Pm));
else, end
else, end
%clc
fprintf('\nInitial power angle = %7.3f \n', d0)
fprintf('Maximum angle swing = %7.3f \n', dmax)
fprintf('Critical clearing angle = %7.3f \n\n', dc)
fprintf('Critical clearing time = %7.3f sec. \n\n', tc)
h = figure; figure(h);
fill(x,y,'m')
hold;
fill(xx,hh,'c')
plot(delta, Pe1,'-', delta, Pe2,'r-', delta, Pe3,'g-', Pmx, Pmy,'b-', x0,y0, xc,yc, xm,ym), grid

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