Simplex optimisation using fminsearch
이전 댓글 표시
Please how can i use the simplex optimisation syntax called 'fminsearch' to optimise a circle fitted to a set of random points? I've tried using the equation of a circle as the function for the syntax but am not making any head way. I presume am not getting the function right.
댓글 수: 7
Walter Roberson
2018년 8월 23일
Ebube Ezi
2018년 8월 23일
Ebube Ezi
2018년 8월 24일
Ebube Ezi
2018년 8월 24일
John D'Errico
2023년 3월 22일
Why do you need to use fminsearch? This is a problem simply solved without recourse to fminsearch.
Bruno Luong
2023년 3월 23일
편집: Bruno Luong
2023년 3월 23일
There are more robust methods https://www.emis.de/journals/BBMS/Bulletin/sup962/gander.pdf
fminsearch is the last thing (even that is unlikely) I would choose.
답변 (2개)
Walter Roberson
2018년 8월 24일
x = vector_of_x_coordinates;
y = vector_of_y_coordinates;
obj = @(xyr) sum( (x-xyr(1)).^2 + (y-xyr(2)).^2 - xyr(3).^2 );
xyr0 = [guess_x, guess_y, guess_r];
[XYR, residue] = fminsearch(obj, xyr0);
댓글 수: 8
Ebube Ezi
2018년 8월 24일
Ebube Ezi
2018년 8월 24일
Walter Roberson
2018년 8월 24일
You can run it as a script. You would need to substitute values for vector_of_x_coordinates and vector_of_y_coordinates
Ebube Ezi
2018년 8월 24일
Biraj Khanal
2023년 3월 21일
편집: Biraj Khanal
2023년 3월 22일
@Walter Roberson, I tried your script like this.
x = C1_w_noise(1,:);
y = C1_w_noise(2,:);
obj = @(xyr) sum( (x-xyr(1)).^2 + (y-xyr(2)).^2 - xyr(3).^2 );
xyr0 = [5,5,1]; % center and radius for C2 as initial guess
[XYR, residue] = fminsearch(obj , xyr0);


But this just runs to a maximum iteration number and stops. I am not sure if I understand the multivariable fminsearch here. Can you help?
EDIT:
the sum function can return in negative value and my assumption is that fminsearch, as shown in the graph allows it to go as low as possible which results in the max iteration . So I added an absolute to the sum. Now, it does try to fit but does not result in anything correct.C3 is the circle from the result of fminsearch.

Walter Roberson
2023년 3월 22일
Ah, I see now that increasing the radius would decrease the sum. I will need to think about a better formula.
Biraj Khanal
2023년 3월 22일
편집: Biraj Khanal
2023년 3월 22일
Shouldn't that be resolved when the absolute value of the sum is used?
Biraj Khanal
2023년 3월 23일
So, this is my adaptation of a tutorial I found. The idea is to minimize the error as distance between the coordinates of guessed circle and the actual data points.
obj = @(hkr) sumerror(hkr,x,y);
[sol ,residue] = fminsearch(obj,[Guess_h, Guess_k, Guess_r]);
function E = sumerror(hkr,x,y)
t=linspace(0,2*pi,length(x));
xx=hkr(1) + hkr(3)*cos(t); % create x and y for the guess iteration
yy=hkr(2) + hkr(3)*sin(t);
Ex=sum((xx-x).^2);
Ey=sum((yy-y).^2);
E=(Ex+Ey)/2; %average of the eror in x and y coordinates
end
It seems to work for me. If anyone gets a simpler idea to do this, it would be great.
You are still looking for help on this?
There is ABSOLUTELY no need to use a simplex optimizer for this problem. NONE AT ALL. Let me make up some data.
n = 50;
XY = normalize(randn(n,2),2,'norm') + 2 + randn(n,2)/5;
plot(XY(:,1),XY(:,2),'.')
axis equal
The data is a circle, with center at [2,2], and a radius of 1.
[C,R,rmse] = circlefit(XY)
theta = linspace(0,2*pi)';
XYhat = C + R*[cos(theta),sin(theta)];
hold on
plot(XYhat(:,1),XYhat(:,2),'r-')
plot(C(1),C(2),'gx')
hold off
So a circle at center pretty near the point [2,2], with radius estimated as also very close to 1.
Even if you have only half an arc of a circle, it still works.
k = XY(:,1) > 2;
plot(XY(k,1),XY(k,2),'.')
axis equal
[C,R,rmse] = circlefit(XY(k,:))
theta = linspace(-pi/2,pi/2)';
XYhat = C + R*[cos(theta),sin(theta)];
hold on
plot(XYhat(:,1),XYhat(:,2),'r-')
plot(C(1),C(2),'gx')
hold off
As expected, the estimates are less good there, but that data is seriously noisy. Honestly, if someone gave me this data and asked to fit a circle to it, I would have guessed the data is almost useless to fit a circle.
I've attached circlefit to this answer. (circlefit also works on higher dimensional data, where it can fit a sphere to data in 3-d, etc.)
Circlefit uses an algebraic trick to remove the quadratic terms in the circle equations. This reduces the problem to finding the best intersection of many straight lines. But that is a problem easily solved using linear algebra. It can also use robustfit from the stats toolbox, if you have it.
Don't write your own code to solve problems like this.
카테고리
도움말 센터 및 File Exchange에서 Linear Algebra에 대해 자세히 알아보기
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!

