Each matrix of the of the cell should be unique/different from each other

I am new to matlab. I have to create a cell in which each matrix is different from the earlier cell entries. Hence i am writng the code such that each matrix is checked before it is stored in cell with all previous matrix in the cell. That means, W{4} would be stored in the cell only if W{1},W{2},W{3} are different from W{4}. Can anyone help ? Thanks in advance.

clc;
clear all;
n = 2;

W=cell(5,1);% Different Matrix
i=1;% initialization
while i<6 % Iterations 
    a = zeros(n+1, 2)
   a(randperm(numel(a), n)) = 1 
   %W{i}=a(:,:);

     A=a(:,:)
     if (sum(A(1,:))>=1) && (sum(A(n+1,:))==0)
         A_new=A(:,:)
         for j=1:i
             * *if W{j}~=W{i} %** Each matrix in the Cell should be different
                 W{j}=A_new
             end

             end

%    elseif sum(A_new(4,:))<=0
           %W{i}=A_new;
           i=i+1;
   end

end

Answer 1

[Stephen23]

One way: use a 3D array, shuffle each matrix so that it is unique:

n = 2;
r = n+1;
z = zeros(r,n,5);
z(1,:,:) = 1;
p = 1;
while p<=size(z,3)
    m = z(:,:,p);
    m = reshape(m(randperm(numel(m))),r,n);
    z(:,:,p) = m;
    p = p+~any(all(all(bsxfun(@eq,m,z(:,:,1:p-1)),1),2),3);
end

Each matrix of z is unique:

>> z
z(:,:,1) =
   1   0
   0   0
   0   1
z(:,:,2) =
   0   0
   0   1
   0   1
z(:,:,3) =
   1   0
   0   1
   0   0
z(:,:,4) =
   0   0
   0   1
   1   0
z(:,:,5) =
   1   0
   0   0
   1   0

Just for fun a very memory-inefficient solution:

>> n = 2;
>> m = zeros(n+1,n);
>> m(1,:) = 1;
>> p = perms(m(:)); % ouch! all permutations!
>> q = p(randi(size(p,1),1,5),:); % random subset
>> z = reshape(q.',n+1,n,[])
z(:,:,1) =
   0   0
   0   0
   1   1
z(:,:,2) =
   0   0
   0   1
   0   1
z(:,:,3) =
   1   0
   0   0
   0   1
z(:,:,4) =
   0   0
   1   1
   0   0
z(:,:,5) =
   1   1
   0   0
   0   0

[P K]

Stephen Cobeldick : 'great'