Matlab continues to run and wont stop. Is my solution to complicated?
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Here is my code
syms x y
a= 13;
b= 5;
c=2;
d=5;
p = 4*(a+b+c+d);
f(x,y)= (p./((3*x+a).^2+(3*y+c).^2+(a+c)))...
-(2*p./((3*x-b).^2+(3*y+d).^2+(b+d)))...
-(3*p./((3*x+a).^2+(3*y-d).^2+(a+d)))...
+(4*p./((3*x-b).^2+(3*y-c).^2+(b+c)));
ezsurf(f,[-10,10])
title('My land');
xlabel('X- Axis');
ylabel('Y-Axis');
colormap(jet)
hold off
fx= diff(f,x);
fy=diff(f,y);
[a,b]= solve(fx,fy);
double([a,b])
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답변 (2개)
Aquatris
2018년 8월 4일
편집: Aquatris
2018년 8월 4일
Try doing this in your code;
fx = simplify(expand(diff(f,x)));
fy = simplify(expand(diff(f,x)));
I think in your code, the expression for fx is too complicated without the simplify(expand()) command. When I replaced that part, it was able to solve in a second or so.
댓글 수: 3
Aquatris
2018년 8월 4일
It worked. I used Matlab online. However as Walter commented, this might not be what you want.
Walter Roberson
2018년 8월 4일
If you try stepwise elimination of either fx or fy with respect to either x or y, you will get a solution involving the roots of a polynomial of order 12. With each of them being order 12, MATLAB has to work through 144 different roots -- but it cannot express them in full because there is not typically any closed form expression for any order above order 4. So this is not an easy equation to solve.
Unfortunately proceeding numerically does not work well in this case: the loss of precision that goes along with working with floating point numbers can result in somewhat negative values being calculated from fx^2+fy^2 even though algebraically that should not be possible.
You appear to be trying to calculate all of the extrema and inflections of f(x,y), including the complex ones.
If you are just looking for the global minima, then it is at about -4.34915949152492498, 1.72539721154691694
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