Hello, How can I plot a figure as below? (3d)

its Pressure amplitude(size 1x32001) against time(size 1x32001) in 6 different location, I have 6 arrays of pressure (6 different places) and time array (same for all 6)

Answer 1

[Star Strider]

I am not certain what you want or what your data actually are.

Try this (with your data, not my created data):

N = 25;
time = linspace(0, 1, N);                               % Row Vector - Created Data
location = linspace(0, 36, 6);
pressure1 = sin(2*pi*time*N + rand);                    % Row Vector - Created Data
pressure2 = sin(2*pi*time*N + rand);
pressure3 = sin(2*pi*time*N + rand);
pressure4 = sin(2*pi*time*N + rand);
pressure5 = sin(2*pi*time*N + rand);
pressure6 = sin(2*pi*time*N + rand);                    % Row Vector - Created Data

pressure = cat(1, pressure1, pressure2, pressure3, pressure4, pressure5, pressure6);

figure
surf(time, location, pressure)
grid on
xlabel('t (s)')
ylabel('x (cm)')
zlabel('P (kPa)')
colorbar(gca, 'westoutside')

This approach concatenates your pressure data vectors to create the matrix the surf function needs for the third argument. You can use vectors for the x and y coordinates.

[Shima Abdullateef]

Thank you so much for your help...so it becomes like the attached image. Because of the number of the points (32001), it becomes completely black. Is there any way that I can solve that?

many thanks,

[Star Strider]

With a dense plot, the colours of the patch edges become dominant. The easiest way to deal with that is to turn off the 'EdgeColor' property.

Example —

figure
hs = surf(rand(500));
set(hs, 'EdgeColor','none')
grid on

See the documentation on Surface Properties (link) for details on this and other properties you can tweak.

Another option is to interpolate the colours.

Example —

figure
surf(rand(500))
shading(gca, 'interp')
grid on

See the documentation on the shading (link) function for details.

The plots these produce are slightly different. Experiment to get the result you want.