Why does imwarp returns single integer uint8 on Homography Projective Transform?

I am trying to map a captured image quadrangle to deskewed view as if viewed from top. My image contains an A4 sheet of paper with some text on it. I have calculated the Homography Matrix H using the corner points and corresponding deskewed points ( 0,0 0,h w,0 & w,h ).
I am expecting an image as output as per imwarp documentation but I am getting a single integer. What am i doing wrong?
Here is the code for doing transformation:
Trial>> H
H =
1.4827 0.1074 -508.2923
0.0122 0.9982 -387.1204
0.0000 0.0000 1.0000
Trial>> tf = projective2d(H);
Trial>> tf
tf =
projective2d with properties:
T: [3×3 double]
Dimensionality: 2
Trial>> imwarp(Image, tf)
ans =
uint8
213
Trial>>

댓글 수: 2

Av Pa
Av Pa 2018년 7월 15일
편집: Av Pa 2018년 7월 15일
2 observations
1. x,y co-ordinates of the identified corners were exchanged. ie x was y and y contained value of x.
2. After switching the values for calculating x and y and taking transpose of the Homography matrix, I get transformed image. But the image is flipped for some reason.
I suggest that you attach the images and the input/output points so that we can attempt to reproduce what you see.

댓글을 달려면 로그인하십시오.

답변 (1개)

the format that the imwarp uses is the transpose of the standard Homography matrix.
just use
tf = projective2d(H')
notice the H' (H transpose).
Hope that helps

질문:

2018년 7월 15일

답변:

2021년 5월 23일

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by