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Stephen23
Stephen23 2018년 6월 30일
편집: Stephen23 2018년 6월 30일

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Easy, given any number of arrays in a cell array C. You could use a loop like this, although it is inefficient because the output array is not preallocated:
C = {[1,2],[3,4],...} % cell array of arrays.
A = C{1};
for k = 2:numel(C)
A = [A;C{k}];
end
Simpler and more efficient would be to concatenate them all at once, without a loop, e.g.:
A = vertcat(C{:})
Whatever you do, do NOT try to access variable names dynamically in a loop! Read this to know why:
Using an array (e.g. a cell array) and indexing is much simpler, neater, much more efficient, less buggy, and easier to debug.

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도움말 센터 및 File Exchange에서 Loops and Conditional Statements에 대해 자세히 알아보기

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2018년 6월 30일

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2018년 6월 30일

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