Hey guys! I wrote a code to study the dynamic of some parameters in a reactor. The problem is that I applied RK, but one of the variables is an explicit equation and, therefore, I'm having trouble to figure it out how to plot the graphic of Tcw2. Can somebody give me an idea? I need Tcw2 versus t (time).....
Thank you! Best regards!
function dx=EstudoDeCaso_RK4(t,x)
%Legenda
%x(1) ---> V
%x(2) ---> h
%x(3) ---> Ca
%x(4) ---> Cb
%x(5) ---> Cc
%x(6) ---> Cd
%x(7) ---> Cw
%x(8) ---> Tr
%Parâmetros
Vu=4; %m³
d=(2*Vu/pi)^(1/3); %m
H=2*d; %m
A=pi*d^2/4; %m²
Vo=0.2; %m³
ve=0.004; %m³/s
Cwe=55; %kmol/m³
Cbe=1; %kmol/m³
Fbe=Cbe*ve*1000; %mol/s
MMa=88/1000; %kg/mol
MMw=18/1000; %kg/mol
MMb=40/1000; %kg/mol
MMmist=(Cbe/(Cbe+Cwe)*MMb+Cwe/(Cbe+Cwe)*MMw); %kg/mol
Cp=75.24; %J/(kmol.K)
Cpa=170.7; %J/(kmol.K)
theta_w=Cwe/Cbe; %(-)
UA=3000; %J/(s.K)
To=300; %K
Tref=273; %K
Tcw1=285; %K
mcw=100; %kg/s
dH=-7.9076E+07; %J/kmol
ko=0.39175; %m³/(kmol.s)
E=5472.7; %K^-1 ----> Ea/R
%Equações Explícitas
Na=x(3)*x(1);
Nb=x(4)*x(1);
Nc=x(5)*x(1);
Nd=x(6)*x(1);
Nw=x(7)*x(1);
NCp=Cp*(Nb+Nc+Nd+Nw)+Cpa*Na;
kd=ko*exp(E*(1/273-1/x(8)));
Kc=10^(3885.44/x(8));
ra=kd*(x(5)*x(6)/Kc-x(3)*x(4));
rb=ra;
rc=kd*(x(3)*x(4)-x(5)*x(6)/Kc);
rd=rc;
Tcw2=x(8)-(x(8)-Tcw1)*exp(-UA/(mcw*Cp));
Qdot=mcw*Cp*(Tcw1-x(8))*(1-exp(-UA/(mcw*Cp)));
%Equações Diferenciais
dx(1)=ve;
dx(2)=ve/A;
dx(3)=ra-ve/x(1)*x(3);
dx(4)=rb+ve/x(1)*(Cbe-x(4));
dx(5)=rc-ve/x(1)*x(5);
dx(6)=rd-ve/x(1)*x(6);
dx(7)=ve/x(1)*(Cwe-x(7));
dx(8)=(Qdot-Fbe*Cp*(1+theta_w)*(x(8)-To)-ra*x(1)*dH)/NCp;
%Vetor linha em vetor coluna
dx=dx';
end

답변 (1개)

Torsten
Torsten 2018년 6월 27일

1 개 추천

Can you plot Tr versus t ?
Then you should also be able to plot
Tr-(Tr-Tcw1)*exp(-UA/(mcw*Cp))
versus t.
Best wishes
Torsten.

댓글 수: 2

Mateus Oliveira Nunes
Mateus Oliveira Nunes 2018년 6월 28일
But could you tell me how? because it isn't working at all
Mateus Oliveira Nunes
Mateus Oliveira Nunes 2018년 6월 28일
I got it! Thank you!

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