- Obviously you can think about starting from surface 2 to match the x and y of surface 1. The difference in the result should be negligible, but this depends on the data.
- I would suggest another measure of the distance, because you can imagine that if the two surfaces cross each other you could have a distance of zero, when actually is not. I would square the difference vector and take its square root as a first attempt.
Compare two matrices/meshgrid/surface/ model digital - distance between models - point data - 3D mesh
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I have 3 vectors fo each surface (meshgrid). I want to compare the distance between this to surfaces. The problem is that to surfaces are not in the same position and the cells of the meshgrid are not on the same size. What i can do to obtain the correct distance between of this tow models?
surf(X,Y,Z); hold on; grid on; hold on, scatter3(NF_P(:,1),NF_P(:,2),NF_P(:,3),'filled'); surfl(X2A,Y2A,Z2A); hold on; scatter3(DD_B2(:,1),DD_B2(:,2),DD_B2(:,3)*(-1),'filled')
i want the difrence between Z and Z2A, but X and Y are difrent from X2A and Y2A.
i make Z3=Z-Z2A, bu is not correct that giv me difrences of 4 meters , that is not true, soo i dont know how to make this analyse
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채택된 답변
Nicola Bombace
2018년 5월 23일
편집: Nicola Bombace
2018년 5월 23일
The first thing you want to do is interpolate the data from one surface to be at the x,y position of the second surface. Then compute the distance from the interpolated surface
Z_int = griddata(X,Y,Z,X2A,Y2A); %interpolate surface 1 to match x,y coordinates of surface 2
Z3 = Z_int - Z2A;
Just two more comments
Hope this helps
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Nicola Bombace
2018년 5월 29일
The issue of cleaning the points is not trivial. I can suggest an algorithm, rather than a specific implementation, and hopefully it will be easy to implement.
- Construct the Mesh with the original points using the delaunayn function
- Determine if a query point is inside your delaunay triangulation using pointLocation function
추가 답변 (1개)
Octavian Macari
2018년 5월 27일
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Nicola Bombace
2018년 5월 29일
If you were to use the code above (the second comment), you could just do:
distMeasure = sqrt(norm(diff));
This will give you a single number that measures the distance of the two surfaces.
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