Problem with concatenation, help me

Hello people, I have a problem: I'm trying to cocatenate the following

arquivo = [arquivo int2str(x) '.FIL']

But when i see the content from "arquivo", we have "CUNOV000.FIL1.FIL" I dont want this ".FIL1", only the ".FILL". after "CUNOV000"

[Paolo]

Could you please post a snippet of code?

[Daniel Fonsêca]

When I write

 arquivo = [arquivo int2str(x) ',' 'FIL']

It's showed

 arquivo = CUNOV000,FIL

but when I type

 arquivo = [arquivo int2str(x) '.' 'FIL']

It showed the same o problem.

[Walter Roberson]

If you do not want the .FIL1 then why do you have the int2str() as apart of what you are adding on?

[John BG]

Hi Daniel

this is John BG <mailto:[e-mail] [e-mail]>

I bet the contents of arquivo already contains the file extension, so you may not be removing the file extension before plugging all strings together.

[Daniel Fonsêca]

When a delete '.FIL' arquivo = CUNOV000 I tried arquivo = [arquivo int2str(x) '.txt'], and arquivo was equal CUNOV000.txt

[Daniel Fonsêca]

the code as Paolo asked

for x = 0:qarq
  arquivo = [arquivo int2str(x)  'FIL']
  [c, msg] = fopen(arquivo);   
  if c < 0
       error('Could not open file "%s" because: "%s"', arquivo, msg);
  end

    da{1,x}= fread(c)
    da{1,x}
    fclose(c);
  end

[Daniel Fonsêca]

I have 6 files which I want read and put the datas into cell array called da.

[Walter Roberson]

http://matlab.wikia.com/wiki/FAQ#How_can_I_process_a_sequence_of_files.3F

Answer 1

[Stephen23]

[~,arquivo] = fileparts(arquivo);
arquivo = sprintf('%s%d.FIL',arquivo,x)

But there is no point in calling fileparts repeatedly in a loop:

[~,fnm] = fileparts(arquivo);
for k = 0:qarq
   tmp = sprintf('%s%d.FIL',fnm,k);
   [fid,msg] = fopen(tmp,'rt');
   assert(fid>=3,msg)
   ...
   fclose(fid);
end