Deriving the time-domain response of an equation, from a tf
조회 수: 60 (최근 30일)
이전 댓글 표시
So I have the code to create a transfer function, from which you can get the graph of the step response:
G = tf([1], [1 0.9 5]);
step(G);
Easy. However I can't find a way to perform an inverse Laplace transform on G, to get an actual equation.
댓글 수: 0
답변 (1개)
Benjamin Großmann
2018년 4월 24일
편집: Benjamin Großmann
2018년 4월 24일
G = tf([1], [1 0.9 5]);
[num,den] = tfdata(G);
syms s
G_sym = poly2sym(cell2mat(num),s)/poly2sym(cell2mat(den),s)
You have to multiply the input in laplace domain to the transfer function to get the system response to a specific input in time domain:
Y_lap_sym = G_sym/s; % U(s) = 1/s for the unit step
y_time_sym = ilaplace(Y_lap_sym);
댓글 수: 2
AAYUSH MARU
2020년 4월 3일
clc;
clear all;
syms t;
t= 0:0.001:10
G = tf([1], [1 0.9 5]);
[num,den] = tfdata(G);
syms s
G_sym = poly2sym(cell2mat(num),s)/poly2sym(cell2mat(den),s)
Y_four_sym = G_sym/s; % U(s) = 1/s for the unit step
y_time_sym = ifourier(Y_four_sym);
y_n = double(y_time_sym);
subplot(2,1,1)
plot(t,y_time_sym);
how to plot step response here?
참고 항목
카테고리
Help Center 및 File Exchange에서 Calculus에 대해 자세히 알아보기
제품
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!