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I have 98x3 matrix with only 7 unique rows of values which are output of some simulation. How do I extract that? I tried Unique function but am not getting unique rows. Below is the original matrix A and matrix after using unique function B.

조회 수: 1 (최근 30일)
A
0 0 0
0 0 0
0 0 0
0 0 0
0 0 0
0 0 0
0 0 0
0 0 0
0 0 0
0 0 0
1.0000 -1.0000 0.0500
0 0 0
0 0 0
0 0 0
0 0 0
0 0 0
0 0 0
0 0 0
0 0 0
0 0 0
0 0 0
1.5000 -0.0000 0.0500
0 0 0
0 0 0
0 0 0
0 0 0
0 0 0
0 0 0
0 0 0
0 0 0
0 0 0
0 0 0
0 0 0
0 0 0
1.0000 1.0000 0.0500
1.0000 1.0000 0.0500
0 0 0
0 0 0
0 0 0
0 0 0
0 0 0
0 0 0
0 0 0
0 0 0
0 0 0
0 0 0
0 0 0
0 0 0
0 0 0
0 0 0
0 0 0
0 0 0
0 0 0
0 0 0
0 0 0
0 0 0
0 0 0
0 0 0
0 0 0
0 0 0
0 0 0
0 0 0
0 0 0
0 0 0
0 0 0
0 0 0
-1.0000 1.0000 0.0500
-1.0000 1.0000 0.0500
0 0 0
0 0 0
0 0 0
0 0 0
0 0 0
0 0 0
0 0 0
0 0 0
0 0 0
0 0 0
0 0 0
0 0 0
-1.5000 -0.0000 0.0500
-1.5000 -0.0000 0.0500
0 0 0
0 0 0
0 0 0
0 0 0
0 0 0
0 0 0
0 0 0
0 0 0
0 0 0
0 0 0
0 0 0
0 0 0
0 0 0
0 0 0
-1.0000 -1.0000 0.0500
-1.0000 -1.0000 0.0500
B=unique(A,'rows')
B
-1.5000 -0.0000 0.0500
-1.5000 -0.0000 0.0500
-1.0000 -1.0000 0.0500
-1.0000 1.0000 0.0500
0 0 0
1.0000 -1.0000 0.0500
1.0000 1.0000 0.0500
1.5000 -0.0000 0.0500

채택된 답변

Rik
Rik 2018년 4월 23일
This is probably due to rounding errors caused by the way doubles are stored in computers. You can use uniquetol instead:
B=uniquetol(A,'ByRows',true);
The tolerance defaults to 1e-6 for single-precision inputs and 1e-12 for double-precision inputs. You can also specify your own tolerance instead.
  댓글 수: 1
akash sonnad
akash sonnad 2018년 4월 25일
Thanks for the hint. Since i was'nt interested in accuracy of data so rounded it off till 3rd decimal digits. It helps !!

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