How to solve the equation?

I have the following code to do fft();

d='cameraman.png';
F=fft2(d);
Fsh=fftshift(F);
s2=log(1+abs(Fsh));

In the fourth step, I wanted to get the value of Fsh, What should be the format to find this in matlab.

I tried doing this operation:

Fsh=round(exp(s2))-1

Can somebody help me with the right format to do this equation in matlab?

[Walter Roberson]

You cannot take the fft of a character string.

Have you considered reading in the file named by the character string?

[Shounak Shastri]

Use 'imread()'to read the file.

But if you want to find the fft of the string, then convert it to integer or double before taking the fft.