xt=[1 2 3 4 5 6 7 8 9 10 11]
for m=1:25
Output supposely
xt1 = [1 2 3 4 5 6 7 8 9 10 11]
xt2 =[1 2 3 4 5 6 7 8 9 10 11]
.
.
.
.
.
.
.
xt25 =[1 2 3 4 5 6 7 8 9 10 11]
What should i do to get this output

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Greg
Greg 2018년 4월 5일
편집: Greg 2018년 4월 5일
You should read any of the umpteen million discussions of why this (dynamically generating variable names) is a bad idea. There is no reason not to use the following with proper indexing:
xt = repmat(1:11,25,1);

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답변 (1개)

Birdman
Birdman 2018년 4월 5일

0 개 추천

Do not dynamically create variables. It is not recommended. Instead, use a multidimensional array:
for m=1:25
xt(:,:,m)=1:11;
end

댓글 수: 1

Why the loop, and why the third dimension?
xt = repmat(1:11,25,1);
Or
xt = repmat(1:11,1,1,25); % If you really want the third dimension

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도움말 센터File Exchange에서 Resizing and Reshaping Matrices에 대해 자세히 알아보기

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